What is the correct radius of the plane's loop?

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Homework Help Overview

The discussion revolves around determining the correct radius of a plane's loop based on the forces acting on a pilot during a loop maneuver. The problem involves concepts from dynamics and circular motion.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss different methods to calculate the radius, including using centripetal acceleration and force equations. There is a comparison of two different results: one suggesting a radius of approximately 1469.39 m and another suggesting 19.36 m. Questions arise about the plausibility of these values and the assumptions behind the calculations.

Discussion Status

Some participants express skepticism about the smaller radius, questioning its feasibility in real-world scenarios. There is an acknowledgment of the need for proper application of the equations involved, with some guidance offered on using force balance correctly.

Contextual Notes

Participants note the importance of considering the physical context of the problem, particularly the implications of the pilot not pushing against the seat belt at the top of the loop.

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A pilot goes into a loop...

A 75 kg pilot goes into a loop. At the top of the loop, where the plane is completely upside down for an instant, the pilot hangs freely in the seat and does not push against the seat belt. The airspeed indicator reads 120m/s. What is the radius of the planes loop?


I did Ac=v^2/r

substitute 9.8 for ac and 120 for v, so...

9.8=120^2/r

and when you do that, the radius is 1469.39 m.


My friend disagrees and says the loop should only be 19.36 meters. He used F=ma, then put that into the equation, to get 19.36.


Can someone say who did it right?
 
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First of all. Which answer is more plausible. Surely I don't see an airplane make a loop with a radius of 19.36 meters.

But more rigorously. The gravitational force on the pilot equals the centrifugal force, since he doesn't push against the seat. So you're right.
 
Thank you, and yes, I had thought of the airplane making a 19m loop. Not going to happen.
 
You could still use F = ma, I don't know why you would, but you'd just you'd have to use it properly.

[tex]F = ma[/tex]
[tex]F = \frac{mv^2}{R}[/tex]
[tex]mg = \frac{mv^2}{R}[/tex]
[tex]g = \frac{v^2}{R}[/tex]
[tex]9.8 = \frac{120^2}{R}[/tex]
...
 

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