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Not only is the symbol daunting, but the words are too

 
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Sep26-11, 07:52 PM   #35
 
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Not only is the symbol daunting, but the words are too

And how would you evaluate (1+0)+1 ?? Is it also 1??
 
Sep26-11, 07:55 PM   #36
 
Quote by micromass View Post
And how would you evaluate (1+0)+1 ?? Is it also 1??
(1 + 0) = 1 from 2.46

so I get 1 + 1 = 0 still

Also RedBelly I was actualyl gonna post my answers lol and then it said "Sorry! the thread is locked!"

Quote by Flyingpig to Redbelly (unrelated to this thread)
Never mind d) is 375. They all move up by 75...each. Stupid question.

This was solutiuon they gave me



Which just means the answer is a multiple of 5, I thought they meant the contours are "5M units apart"
 
Sep26-11, 08:01 PM   #37
 
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OK, so that is indeed correct. We indeed have that

1 + (0 + 1) = (1 + 0) + 1 = 0

But that is not were the error was. The error is in the following

1 + (1 + 0) = (1 + 1) + 0 = 1 + 0 = 1

So can you calculate

1+(1+0)=...
(1+1)+0=...

again and see where the error is?
 
Sep26-11, 08:04 PM   #38
 
Quote by micromass View Post

So can you calculate

1+(1+0)=...
(1+1)+0=...

again and see where the error is?
But they all arrive at the same answer

1 + (1 + 0) = 1 + 1 = 0

(1 + 1) + 0 = 0 + 0 = 0

But 1 + (1 + 0) from A2 says 1 + (1 + 0) = (1 + 1) + 0 = 0 + 0

I don't see the error
 
Sep26-11, 08:12 PM   #39
 
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Quote by flyingpig View Post
But they all arrive at the same answer

1 + (1 + 0) = 1 + 1 = 0

(1 + 1) + 0 = 0 + 0 = 0

But 1 + (1 + 0) from A2 says 1 + (1 + 0) = (1 + 1) + 0 = 0 + 0

I don't see the error
Indeed, they are all 0. But before you said that it was equal to 1. So now you have the correct answer.
 
Sep26-11, 08:14 PM   #40
 
Impossible I had 0!!! It was in post#29!!!

Oh well at least I got the other 7 right! ahahhaah

Wait, does that mean I will have 8 x 8 = 64 lines to write for all the other ones...?
 
Sep26-11, 08:17 PM   #41
 
Correction * 64
 
Sep26-11, 08:19 PM   #42
 
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Yes, now try to do the other ones. This should be quite easy if you understood this one.
 
Sep26-11, 08:20 PM   #43
 
oH MY GOD, Please stay with me in case I made a silly mistake. With 64, I will...
 
Sep26-11, 08:25 PM   #44
 
A1 done, A2 speaks for itself.

Quote by A2

x + y = y + x

Let x = 0, y = 0

0 + 0 = 0 + 0 = 0

Let x = 0, y = 1

0 + 1 = 1 + 0 = 1

Let x = 1, y = 0

1 + 0 = 0 + 1 = 1

Let x = 1, y = 1

1 + 1 = 1 + 1 = 0
OKay probably not 64 then

Quote by A3

I sense danger from this one...

x + 0 = x

Let x = 0

0 + 0 = 0

[b]Let x = 1[/tex]

1 + 0 = 1
Quote by A4
x + (-x) = 0

Oh boy

Let x = 0

0 + (-0) = 0 + 0 = 0

Let x = 1

1 + (-1) =....
Stuck already...I am an idiot

DOing M1-M4 D in another post.
 
Sep26-11, 08:33 PM   #45
 
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OK, for A4, you need to use that -1=1 and -0=0. You define this to be so.
 
Sep26-11, 08:40 PM   #46
 
Quote by M1
Damn it, 8 cases again

(xy)z = x(yz)

Let x = 0, y = 0, z = 0

(0*0)0 = 0(0*0) = 0*0 = 0

Let x = 0, y = 0, z = 1

(0*0)1 = 0(0*1) = 0*0 = 1

Let x = 0, y = 1, z = 0

(0*1)0 = 0(1*0) = 0*0 = 0

Let x = 1, y = 0, z = 0

(1*0)*0 = 1(0*0) = 1*0 = 0

Let x = 1, y = 1, z = 0

(1*1)0 = 1(1*0) = 1*0 = 0

Let x = 1, y = 0, z = 1

(1*0)1 = 1(0*1) = 1*0 = 0

Let x = 0, y =1, z = 1

(0*1)1 = 0(1*1) = 0*1 = 0


Let x = 1, y = 1, z = 1

(1*1)1 = 1(1*1) = 1*1 = 1
Quote by M2

xy = yx

Let x = 0, y = 0

0*0 = 0*0 = 0

Let x = 0, y = 1

0*1 = 1*0 = 0

Let x = 1, y = 0

1*0 = 0*1 = 0

Let x = 1, y = 1

1*1 = 1*1 = 1
Quote by M3

Other than 0, there is a 1 such that x * 1 = x

Let x = 0

0 * 1 = 0

Let x = 1

1*1 = 1
Quote by M4

Other than 0, we have an inverse for x

Oh wait...should I just do x = 1 case...?
Quote by D

NOOO ANOTHER 8 CASE. I'll be back on this one...
Need water...be back in 2 mins.
 
Sep26-11, 08:43 PM   #47
 
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The second of M1 is incorrect.
 
Sep26-11, 09:01 PM   #48
 
Yes because 0*0 is not 1...!

Quote by D

Let x = 0, y = 0, z = 0

0(0 + 0) = 0*0 + 0*0 = 0 + 0 = 0

Let x = 0, y = 0, z = 1

0(0 + 1) = 0*0 + 0*1 = 0 + 0 = 0

Let x = 0, y =1, z = 0

0(1 + 0) = 0*1 + 0*0 = 0 + 0 = 0

Let x = 1, y = 0, z = 0

1(0 + 0) = 1*0 + 1*0 = 0 + 0 = 0

Let x = 1, y = 1, z = 0

1(1 + 0) 1*1 + 1*0 = 1 + 0 = 1

Let x = 1, y = 0, z = 1

1(0 + 1) = 1*0 + 1*1 = 0 + 1 = 1

Let x = 0, y = 1, z = 1

0(1 + 1) = 0*1 + 0*1 = 0 + 0 = 0

Let x = 1, y = 1, z = 1

1(1 + 1) = 1*1 + 1*1 = 1 + 1 = 0
I am pretty confident in this one
 
Sep26-11, 09:08 PM   #49
 
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Looks ok!!
 
Sep26-11, 09:09 PM   #50
 
Now just imagine I have to put all of this on paper.
 
Sep26-11, 09:53 PM   #51
 
Quote by SammyS View Post
For this field, -1 = 1 . This is because the thing you need to add to 1 to give you the identity element for addition is 1.
Quote by micromass View Post
OK, for A4, you need to use that -1=1 and -0=0. You define this to be so.
I overlooked something. since WHEN DID I DEFINE -1 = 1?
 
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