Calculating the current in a solenoid

In summary, the problem involves finding the current in a short-circuited solenoid with given resistance and inductance values, rotating in a uniform magnetic field at an angular velocity. To find the current, one must first find the magnetic field using Faraday's law of induction and then treat the problem as a series circuit.
  • #1
couponcoocoo
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Homework Statement



A short-circuited solenoid of radius b with n turns rotates at an angular velocity
about the diameter of one of the turns in a uniform magnetic field B. The axis of rotation is perpendicular to the magnetic field direction. The resistance and the inductance of the solenoid are equal to R and L, respectively. Find the current in the solenoid as a function of time

Homework Equations



Hint eq: phi = normal vector (dot) Magnetic field (B) s


The Attempt at a Solution



i can't seem to figure out where to start. in order to find the current in the solenoid, do i have to first start with finding the magnetic field (or a specific value of B)? and then plug that into the above eq?
 
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  • #2
See the first page of,

http://hyperphysics.phy-astr.gsu.edu/hbase/electric/farlaw.html

There is a small error in the first page of the link above, can you find it?

Once you get the induced sinusoidal voltage you can treat the problem as a series circuit consisting of a sinusoidal voltage a resistance and an inductor?

Found via,

http://www.google.com/webhp?hl=en#h...w.,cf.osb&fp=e47bbecef463087a&biw=721&bih=408

See also,

http://www.google.com/search?hl=en&...&um=1&ie=UTF-8&tbm=isch&source=og&sa=N&tab=wi
 

What is a solenoid?

A solenoid is a type of electromagnet that consists of a coil of wire wrapped around a cylindrical core. When an electric current is passed through the wire, it creates a magnetic field that can be used for various purposes such as generating motion or controlling other electrical components.

How is the current calculated in a solenoid?

The current in a solenoid can be calculated using the equation I = B * n * A, where I is the current in amperes, B is the magnetic field strength in teslas, n is the number of turns in the coil, and A is the cross-sectional area of the solenoid. This equation is known as Ampere's Law.

What factors affect the current in a solenoid?

The current in a solenoid is affected by the number of turns in the coil, the strength of the magnetic field, and the cross-sectional area of the solenoid. Additionally, the material of the core and the resistance of the wire can also affect the current.

Can the current in a solenoid be varied?

Yes, the current in a solenoid can be varied by changing the voltage applied to the coil or by altering the number of turns in the coil. This change in current will also affect the strength of the magnetic field produced by the solenoid.

How is the direction of the current in a solenoid determined?

The direction of the current in a solenoid can be determined by the right-hand rule. If you point your right thumb in the direction of the current, then your fingers will curl in the direction of the magnetic field lines. This rule can also be used to determine the direction of the force on a current-carrying wire placed in the magnetic field of a solenoid.

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