
#37
Oct111, 02:10 AM

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P: 11,451

Gotta go catch some zZ's now. I'll check back in the morning (my morning, that is).




#38
Oct111, 02:11 AM

P: 116

I think that my answer is wrong because when I used this equation on a different question with the same circuit with the voltage source being 4V, R1 = 1600, R = 2000 and C = 10n the answer I got was 0.798V but the correct answer is 1.4239V.




#39
Oct111, 09:44 AM

Mentor
P: 11,451

Good morning. (*YAWN*)
I took another look at the problem. A small correction is required to the time response formula. This time the exponential is starting at zero and heading towards a final value that's equal to the Thevenin voltage of the resistor network. So the form is: [tex] V_o(t) = V_{th} \left(1  e^{t/\tau} \right) [/tex] Regarding your "different question with the same circuit", apply the above suggested formula and recheck your result  also check to see if the time t1 to be plugged in is the same for both problems. 



#40
Oct111, 08:45 PM

P: 116

ok cool i got the answer. Now for the second part of the question with the switch between the resistor and the voltage source, my answer for the time before and after 0 as 0V and it is going to 5(7500/17500) = 2.143V.




#41
Oct111, 09:19 PM

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P: 11,451





#42
Oct111, 09:31 PM

P: 116

ok thanks i got the answer



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