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How to find magnitude of centripetal acceleration and of net force?

by starplaya
Tags: acceleration, centripetal, force, magnitude
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starplaya
#1
Oct2-11, 04:57 PM
P: 9
1. The problem statement, all variables and given/known data
A ferris wheel at a carnival has a radius of 12 m and turns so that the speed of the riders is 8m/s
a) what is the magnitude of the centripetal acceleration of the riders?
b) what is the magnitude of the net force required to produce this centripetal acceleration for a rider with a mass of 70kg?


2. Relevant equations

Centripetal acceleration = v^2/r
F = ma
Fnet = N - W = m(centripetal acceleration)

3. The attempt at a solution

centripetal acceleration = 8^2/ 12 = 5.33 m/s^2
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Doc Al
#2
Oct2-11, 04:59 PM
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Quote Quote by starplaya View Post
centripetal acceleration = 8^2/ 12 = 5.33 m/s^2
Looks good.
starplaya
#3
Oct2-11, 05:22 PM
P: 9
Quote Quote by Doc Al View Post
Looks good.
so, 5.33 m/s^2 would be the answer for part A and for part B i just multiply the acceleration by the mass?

Doc Al
#4
Oct2-11, 05:25 PM
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How to find magnitude of centripetal acceleration and of net force?

Quote Quote by starplaya View Post
so, 5.33 m/s^2 would be the answer for part A and for part B i just multiply the acceleration by the mass?
That's correct.
starplaya
#5
Oct2-11, 05:46 PM
P: 9
Boy was I over thinking that. Thanks a lot for the clarification


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