# How to find magnitude of centripetal acceleration and of net force?

by starplaya
Tags: acceleration, centripetal, force, magnitude
 P: 9 1. The problem statement, all variables and given/known data A ferris wheel at a carnival has a radius of 12 m and turns so that the speed of the riders is 8m/s a) what is the magnitude of the centripetal acceleration of the riders? b) what is the magnitude of the net force required to produce this centripetal acceleration for a rider with a mass of 70kg? 2. Relevant equations Centripetal acceleration = v^2/r F = ma Fnet = N - W = m(centripetal acceleration) 3. The attempt at a solution centripetal acceleration = 8^2/ 12 = 5.33 m/s^2
Mentor
P: 41,477
 Quote by starplaya centripetal acceleration = 8^2/ 12 = 5.33 m/s^2
Looks good.
P: 9
 Quote by Doc Al Looks good.
so, 5.33 m/s^2 would be the answer for part A and for part B i just multiply the acceleration by the mass?

Mentor
P: 41,477
How to find magnitude of centripetal acceleration and of net force?

 Quote by starplaya so, 5.33 m/s^2 would be the answer for part A and for part B i just multiply the acceleration by the mass?
That's correct.
 P: 9 Boy was I over thinking that. Thanks a lot for the clarification

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