Transformations proof

bifodus

Let S:V --> W and T:U --> V be linear transformations. Prove that
a) if S(T) is one-to-one, then T is one-to-one
b) if S(T) is onto, then S is onto

This makes intuitive sense to me, since S(T) maps U to W, but I can't figure out how to go about proving this.

I would appreciate any help at all. Thank you.

arildno

a) Suppose that T is not one-to-one, but S(T) is one-to one.
Since there exist at least u1, u2 in U, so that T[u1]=T[u2]=v1,
then we would have S(T[u1])=S[v1]=S(T[u2])=w1, i.e, we have a contradiction, since S(T) is premised to be one-to-one.

Similar Threads for: Transformations proof
Thread	Forum	Replies
Proof: Compare two integral(Please look at my surgested proof)	Calculus & Beyond Homework	11
Gauge Transformations and (Generalized) Bogoliubov Transformations.	Quantum Physics	8
Unitary Transformations proof	Advanced Physics Homework	13
Proof of composite linear transformations	Linear & Abstract Algebra	1
A proof is a proof---says Canadian Prime Minister	General Math	0

bifodus	Transformations proof Tweet Let S:V --> W and T:U --> V be linear transformations. Prove that a) if S(T) is one-to-one, then T is one-to-one b) if S(T) is onto, then S is onto This makes intuitive sense to me, since S(T) maps U to W, but I can't figure out how to go about proving this. I would appreciate any help at all. Thank you.

arildno Recognitions: Gold Member Homework Help Science Advisor	a) Suppose that T is not one-to-one, but S(T) is one-to one. Since there exist at least u1, u2 in U, so that T[u1]=T[u2]=v1, then we would have S(T[u1])=S[v1]=S(T[u2])=w1, i.e, we have a contradiction, since S(T) is premised to be one-to-one.