Finding the Walking Speed: Solving for Velocity with 440Hz and Speed of Sound

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Homework Help Overview

The problem involves two loudspeakers producing 440Hz tones and a listener walking between them, experiencing changes in loudness at a frequency of 3.0 Hz. The speed of sound is given as 343 m/s, and the goal is to determine the listener's walking speed.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the Doppler effect and the observed frequency changes as the listener moves between the speakers. There is exploration of the concept of constructive and destructive interference of sound waves and how this relates to the listener's experience of loudness.

Discussion Status

Participants are actively engaging with the problem, questioning assumptions about the frequency observed and the nature of the interference pattern. Some guidance has been offered regarding the relationship between the distance of constructive interference points and the wavelength of sound, although there is no explicit consensus on the final approach to finding the walking speed.

Contextual Notes

There are discussions about the relevance of the distance between the speakers and the relationship between the frequency of loudness changes and the listener's walking speed. Participants are also considering the implications of the beat frequency and the spacing of nodes and anti-nodes in the sound wave pattern.

NotaPhysicsMan
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Hey,

My question:

Two loudspeakers face each other, vibrate in phase, and produce identical 440Hz tones. A listener walks from one speaker toward the other at a constant speed and hears the loudness change (loud-soft-lound) at a frequency of 3.0 Hz. The speed of scound is 343m/s What is the walking speed?

Ok, where do I start?

I can find the wavelength with 440Hz, and speed of sound.
I'm guessing V=d/t? to find the walking speed. Help!
 
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If the two vibrations are in phase, they are adding or reinforcing each other.

What happens when an observer moves toward or away from an acoustic source? Doppler shift.
 
See, the observer is moving from one speaker to another, so it's moving away from a source to a source. Is the frequency observed 3Hz, or is that the beat frequency?
 
:rolleyes: Astronuc..? Still confused here lol.
 
The doppler effect can't work here?
 
Consider that the sound waves from each speaker will interfere with each other, creating a standing wave pattern. What's the spacing between the anti-nodes? (Hint: anti-nodes occur where the waves constructively interfere. For example, right in the middle between the speakers will be a spot where the waves are in phase.)
 
hmm, let me see if I can get where you're going. The distance between the two speakers, let's say L. I want to find L do I can see what distance the man will walk, then find velocity, but I need time. Ok, I can find L from L=v/2f?
 
The distance between speakers is irrelevant. Find the distance between the points of constructive interference. (Hint: That distance is related to the wavelength of the sound.)
 
The spacing between the antindoes? isn't that dependent on the harmonics? if it was the 1st it would lambda/2, if it was the 2nd, then lambda? Wait, that's for nodes, for the 2nd the distance is lambda/2.
 
  • #10
Another thing(s): it says (loud-soft-lound), doesn't that mean when loud, we get constructive, soft -destructive. So wouldn't there be a node in the middle? I don't see how finding this will lead to the man's velocity, not yet anyway.
 
  • #11
NotaPhysicsMan said:
Another thing(s): it says (loud-soft-lound), doesn't that mean when loud, we get constructive, soft -destructive. So wouldn't there be a node in the middle?
Yes. The anti-nodes are separated by nodes.
I don't see how finding this will lead to the man's velocity, not yet anyway.
If you know the distance between anti-nodes (or nodes) and the man's walking speed you can figure out the frequency of loudness changes that he hears. For example: if the anti-nodes were 2 feet apart, and the man walked 2 feet per second, then he'd hear the sound alternate from loud-to soft-to loud every second: 1 Hz.
 
  • #12
But we dont' know the man's walking speed. Wait, so let's say that the distance between the antinodes were lambda/2. So to find lambda, lambda=speed of sound/frequency. So 343m/s / 440hz. ok so 0.77m/2 as distance between antinodes is lambda/2. I get 0.40m. He hears loudsoftloud at 3hz which is 0.33s. V=d/t, that would be .40m/0.33s, I get 1.20 m/s?
 
  • #13
Sounds good to me.
 
  • #14
Yes, Thanks!
 

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