## Z (conjugate) not analytic?

1. The problem statement, all variables and given/known data

Show that f(z) = ¯z is not differentiable for any z ∈ C.

2. Relevant equations

3. The attempt at a solution

Is it because the Cauchy-Reimann Equations don't hold?

Z (conjugate) = x-iy
u(x,y)=x
v(x,y=-iy

du/dx=1≠dv/dy=-1
du/dy=0≠-dv/dx=0

Edit: Is there another approach? Because the CR Equations is something we learned later on.
 PhysOrg.com science news on PhysOrg.com >> Ants and carnivorous plants conspire for mutualistic feeding>> Forecast for Titan: Wild weather could be ahead>> Researchers stitch defects into the world's thinnest semiconductor

Recognitions:
Homework Help
 Quote by Applejacks 1. The problem statement, all variables and given/known data Show that f(z) = ¯z is not differentiable for any z ∈ C. 2. Relevant equations 3. The attempt at a solution Is it because the Cauchy-Reimann Equations don't hold? Z (conjugate) = x-iy u(x,y)=x v(x,y=-iy du/dx=1≠dv/dy=-1 du/dy=0≠-dv/dx=0 Edit: Is there another approach? Because the CR Equations is something we learned later on.
Sure. Use the definition of f'(z)=lim h->0 (f(z+h)-f(z))/h. Show the limit is different if you pick h to be real from the limit if you pick h to be imaginary. That's really what the content of the CR equations is.
 I think I get it now. (f(z+h)-f(z))/h (conjugate((z+h)-z))/h = h(conjugate)/h If h=Δx, the ratio equals 1 If h=Δiy, the ratio equals -1. Since the two approaches don't agree for any z, z(conj) is not analytic anywhere. Correct?

Recognitions:
Homework Help