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Ti89 Titanium "too few arguments"

 
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Oct29-11, 10:22 AM   #1
 

Ti89 Titanium "too few arguments"


sorry for my noobieness, but I'm having problem with my mod( function on my Ti89 Titanium

On other calcs: 54 mod 10 = 4
like here: http://www.google.com/search?q=54+mod+10

But when i use the mod( function I either get "to few arguments" og just the result 54.mod10

can anyone point me to what I'm doing wrong?
 
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Oct29-11, 12:08 PM   #2
 
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Welcome to PF, Spagnum!

Have you tried mod(54,10)?
 
Oct29-11, 12:15 PM   #3
 
Thank you!

yes I have - that just results in "Too few arguments"
 
Oct29-11, 12:34 PM   #4
 
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Ti89 Titanium "too few arguments"


Quote by Spagnum View Post
Thank you!

yes I have - that just results in "Too few arguments"
Ah well, I do not own a Ti89, but this page: http://www.prenhall.com/esm/app/grap...nu/number.html
shows that mod(-5,8) --> 3 should work, complete with screenshot.
 
Oct29-11, 03:21 PM   #5
 
Yup I been to that page myself but I get the same result.(Too few arguments) I even reset the calculator, in case it had something to do with some settings.
 
Oct29-11, 03:26 PM   #6
 
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Quote by Spagnum View Post
Yup I been to that page myself but I get the same result.(Too few arguments) I even reset the calculator, in case it had something to do with some settings.
The one reason I can think it might say "too few arguments", is if there's a problem with the decimal point, in which case you'd have tried to calculate mod(54.10, ???)
You sure you used a comma?
Or perhaps you could try a semicolon?
 
Oct29-11, 03:41 PM   #7
 
ofc... the comma.
I'm so use to working in Excel where . is the comma, and haven't used my calculator in ages.

Anyways it works like a charm now, thanks a lot for your help Serena!
 
Oct29-11, 03:43 PM   #8
 
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You're welcome!
 
Oct29-11, 03:46 PM   #9
 
Admin
On my TI-89 (but not Titanium) mod(54,10) gives correct 4.
 
Oct29-11, 04:23 PM   #10
 
Mentor
The old UK versus USA, comma versus period switcheroo, eh?
 
Oct29-11, 04:32 PM   #11
 
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Uhh I've never heard of using a period as an argument separator?
 
Feb18-12, 11:01 AM   #12
 
Hey I am also a noob and I need help.
I made this program to calculate the area of a sector and I keep getting "Too Few Arguments"
The ø is a theta and the 'arrow' is the arrow made by STO


area_sec()
Prgm
Local a,r,g,s,ø,k
Dialog
Request "Press 1 if you have rs and 2 if you have rø"a
EndDlog
If a=1 Then
Dialog
Request "Enter r",r
Request "Enter s",s
EndDlog
expr(-r) 'arrow' r
expr(s) 'arrow' s
(1/2)*r*s 'arrow' k
Disp "Area is"&string(k)
Else If a=2 Then
Dialog
Request "Enter r",r
Request "Enter ø",ø
Dialog
expr(-r) 'arrow' r
expr(s) 'arrow' s
(1/2)*r*r*ø 'arrow' k
Disp "Area is"&string(k)
Else
EndIf
DelVar a,r,s,ø,k
EndPrgm
 
Aug4-12, 04:39 PM   #13
 
Look at line 5 again:

Request "Press 1 if you have rs and 2 if you have rø"a
You forgot a comma in between your "request" and your variable, like so:

Code:
Request "Press 1 if you have rs and 2 if you have rø",a
Try that and see what you get.
 
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