Determine charge stored in capacitor

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The discussion centers on calculating the charge stored in a 50 μF capacitor charged by a 6V battery and the time constant of the circuit when discharged through a 100kΩ resistor. The charge (Q) can be determined using the formula Q = C × V, resulting in Q = 50 μF × 6V = 300 μC. The time constant (τ) of the RC circuit is calculated using τ = R × C, yielding τ = 100kΩ × 50 μF = 5 seconds.

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Hey,
I am stuck on a question on capacitors, I have been doing physics all day so my brain might just be fizzled out a bit, but it is bugging me so if anyone could help it would great.Thanks,

A 50 μF capacitor is charged by connecting it to a 6V battery then discharged through a 100kΩ resistor.

Calculate the charge stored in the capacitor immediately after it has been charged and the time constant of the circuit.
 
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If the capacitor's connected directly to the battery, use C = Q/V for the first bit. The time constant, τ = RC for an RC circuit.
 
thank you :smile:
 

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