
#1
Nov2211, 02:48 PM

P: 8

this here is the problem....
Use the equations below. (Note that the direction is indicated by the sign in front of the equations.) x = (0.0553 m) cos(4.094t + 0.14π) v = −(0.226 m/s) sin(4.094t + 0.14π) a = −(0.927 m/s2) cos(4.094t + 0.14π) (a) Determine the first time (t > 0) that the position is at its maximum (positive) value. s (b) Determine the first time (t > 0) that the velocity is at its maximum (positive) value. s i have no idea where to start, or how to do this. 



#2
Nov2211, 02:52 PM

P: 939

Position is given by x.
At what angle is the cos(...) maximum? 



#3
Nov2211, 02:55 PM

P: 8

they didnt give an angle. but I'm guessing since we want x to equal what ever number is there, then cos must equal 1 right?




#4
Nov2211, 03:02 PM

P: 939

need help getting started
so (0.0553 m) cos(4.094t + 0.14π) is max when cos(4.094t + 0.14π) = 1
that is when (4.094t + 0.14π) = ....? 


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