need help getting started


by lefthand
Tags: started
lefthand
lefthand is offline
#1
Nov22-11, 02:48 PM
P: 8
this here is the problem....

Use the equations below. (Note that the direction is indicated by the sign in front of the equations.)
x = (0.0553 m) cos(4.094t + 0.14π)

v = −(0.226 m/s) sin(4.094t + 0.14π)

a = −(0.927 m/s2) cos(4.094t + 0.14π)

(a) Determine the first time (t > 0) that the position is at its maximum (positive) value.
s

(b) Determine the first time (t > 0) that the velocity is at its maximum (positive) value.
s

i have no idea where to start, or how to do this.
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grzz
grzz is offline
#2
Nov22-11, 02:52 PM
P: 939
Position is given by x.

At what angle is the cos(...) maximum?
lefthand
lefthand is offline
#3
Nov22-11, 02:55 PM
P: 8
they didnt give an angle. but I'm guessing since we want x to equal what ever number is there, then cos must equal 1 right?

grzz
grzz is offline
#4
Nov22-11, 03:02 PM
P: 939

need help getting started


so (0.0553 m) cos(4.094t + 0.14π) is max when cos(4.094t + 0.14π) = 1

that is when (4.094t + 0.14π) = ....?


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