Register to reply

Need help getting started

by lefthand
Tags: started
Share this thread:
lefthand
#1
Nov22-11, 02:48 PM
P: 8
this here is the problem....

Use the equations below. (Note that the direction is indicated by the sign in front of the equations.)
x = (0.0553 m) cos(4.094t + 0.14π)

v = −(0.226 m/s) sin(4.094t + 0.14π)

a = −(0.927 m/s2) cos(4.094t + 0.14π)

(a) Determine the first time (t > 0) that the position is at its maximum (positive) value.
s

(b) Determine the first time (t > 0) that the velocity is at its maximum (positive) value.
s

i have no idea where to start, or how to do this.
Phys.Org News Partner Science news on Phys.org
Apple to unveil 'iWatch' on September 9
NASA deep-space rocket, SLS, to launch in 2018
Study examines 13,000-year-old nanodiamonds from multiple locations across three continents
grzz
#2
Nov22-11, 02:52 PM
P: 950
Position is given by x.

At what angle is the cos(...) maximum?
lefthand
#3
Nov22-11, 02:55 PM
P: 8
they didnt give an angle. but I'm guessing since we want x to equal what ever number is there, then cos must equal 1 right?

grzz
#4
Nov22-11, 03:02 PM
P: 950
Need help getting started

so (0.0553 m) cos(4.094t + 0.14π) is max when cos(4.094t + 0.14π) = 1

that is when (4.094t + 0.14π) = ....?


Register to reply

Related Discussions
I want to get started now Academic Guidance 16
Just getting started General Physics 2
Getting started General Math 6
How to get started? Special & General Relativity 2
Can't get started Introductory Physics Homework 1