Forces and Pressure in a Hydraulic System


by forestmine
Tags: forces, hydraulic, pressure
forestmine
forestmine is offline
#1
Dec8-11, 03:26 PM
P: 182
1. The problem statement, all variables and given/known data
The small piston of a hydraulic lift has a diameter of 8.0 cm, and its large piston has a diameter of 40 cm. The lift raises a load of 15,000 N.

(a) Determine the force that must be applied to the small piston.

(b) Determine the pressure applied to the fluid in the lift.


2. Relevant equations

p=F/A

3. The attempt at a solution

I correctly solved for part a, and came up with an answer of 600 N. I'm a little unclear about how to obtain the answer for part b. My thought was that since pressure = F/A, I could simply take the pressure I found from part a, and divide by the area of the smaller piston, but I'm not getting the correct answer...

Thanks in advance!
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obafgkmrns
obafgkmrns is offline
#2
Dec8-11, 04:50 PM
P: 126
You're doing it correctly. Could the problem be one of units? Pressure is often stated in newtons/meter^2 (i.e., pascals). Note that 8.0 cm = 0.08 m.
forestmine
forestmine is offline
#3
Dec8-11, 06:09 PM
P: 182
EDIT// I must have been making a calculation error. I figured it out.

Thank you!


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