
#1
Dec811, 03:26 PM

P: 182

1. The problem statement, all variables and given/known data
The small piston of a hydraulic lift has a diameter of 8.0 cm, and its large piston has a diameter of 40 cm. The lift raises a load of 15,000 N. (a) Determine the force that must be applied to the small piston. (b) Determine the pressure applied to the fluid in the lift. 2. Relevant equations p=F/A 3. The attempt at a solution I correctly solved for part a, and came up with an answer of 600 N. I'm a little unclear about how to obtain the answer for part b. My thought was that since pressure = F/A, I could simply take the pressure I found from part a, and divide by the area of the smaller piston, but I'm not getting the correct answer... Thanks in advance! 



#2
Dec811, 04:50 PM

P: 126

You're doing it correctly. Could the problem be one of units? Pressure is often stated in newtons/meter^2 (i.e., pascals). Note that 8.0 cm = 0.08 m.




#3
Dec811, 06:09 PM

P: 182

EDIT// I must have been making a calculation error. I figured it out.
Thank you! 


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