Distance calculated from Energy

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 Recognitions: Homework Help Complete the following so the sentences are true: The particle starts with ________J kinetic energy. Work done on the particle increases/decreases it's kinetic energy. Now how is the Work related to the distance the particle travels? To help you properly, really need to see your working.
 The particle starts with 0 J kinetic energy. Force relates the work to the distance the particle travels.

Recognitions:
Homework Help

Distance calculated from Energy

 The particle starts with 0 J kinetic energy.
Doesn't the particle have some initial velocity?

Select "increases" or "decreases" for the second sentence.

 Well, at x=0, the Force is 2 Newtons but the x is 0, so wouldn't 2N * 0m = 0 J? Work done on the particle increases it's kinetic energy.
 Recognitions: Homework Help OK - you've forgotten about the initial velocity. When I read part (b) I see this: (b) if it starts with a velocity of 2m/s in the +x direction, how far will the particle go in that direction before stopping? Thus - how much kinetic energy is it starting with?
 Ooh okay, it's 1 J.
 Recognitions: Homework Help No worries - the eye sometimes skips part of a question. Hate it when that happens :)
 Thanks :] So once I have 1 J, how do I solve for the distance? I added 1 J to the 3 J at x = 4. W = fd so.. 4 J = F d. What would be my F?
 Recognitions: Homework Help You don't need F. Look at your graph. You did it correctly when you thought you started with 0J energy - do the same thing only starting with 1J So - you start with 1J In the first meter moved, you gain 1J (area under F-x graph) for a total of 2J What happens in the next meter moved? How far before you've lost all the KE?
 2.5m! Thanks so much, I really appreciate your help :)