Work (Physics)

by Drey0287
Tags: physics, work
 P: 208 Work (Physics) Question: A 50-kg crate is pulled 40 m along a horizontal floor by a constant 100 N force exerted by a person which acts at a 37 degree angle above the horizontal. Determine the work done on the crate. Solution: Work=(Force)(Displacment)(COS degrees) $$W=fdcos$$ $$=(100)(40)(Cos 37)$$ $$=(100)(40)(0.80)$$ $$=3200 J$$ $$=3.2 kJ$$ I might be wrong.