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Smithf
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I have read that 3 pion decay of the eta is not allowed as a strong reaction, but proceeds as an electromagnetic interaction. I do not see why it is strong forbidden.
The 3 pion decay of eta (η) is strongly forbidden due to the conservation of isospin and angular momentum. This decay violates the conservation of isospin by transforming the eta particle, which has isospin 0, into three pions, each with isospin 1. It also violates the conservation of angular momentum by producing three pions with a total spin of 0, while the eta particle has a spin of 0.
The conservation of isospin requires that the total isospin of the particles involved in a decay process remain constant. In the case of the 3 pion decay of eta (η), the eta particle has isospin 0 while the three pions each have isospin 1. This violates the conservation of isospin and thus the decay is strongly forbidden.
The 3 pion decay of eta (η) violates the conservation of angular momentum because it produces three pions with a total spin of 0, while the eta particle has a spin of 0. Conservation of angular momentum requires that the total spin of particles involved in a decay process remains constant.
The 3 pion decay of eta (η) can occur under certain rare circumstances, such as in the presence of strong electromagnetic fields or in high-energy collisions. In these cases, the conservation of isospin and angular momentum can be temporarily violated, allowing for the decay to occur.
Yes, there are several other particles whose 3 pion decay is strongly forbidden due to the same conservation laws. These include the omega (ω) and phi (φ) mesons, which also have isospin 0 and spin 0, and the D and B mesons, which have isospin 0 and spin 1. In all of these cases, the 3 pion decay is forbidden due to the violation of isospin and angular momentum conservation.