Rotation: the earth-moon system

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The discussion revolves around the angular momentum of the Earth-moon system, including the rotational dynamics of both the Earth and the moon. Participants explore the calculations related to angular momentum and torque, considering the effects of internal torques on the Earth's rotation period.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss calculating the angular momentum of the Earth-moon system by considering both the individual rotations of the Earth and moon and their orbital motion around a common center of mass. Questions arise about the appropriate formulas and assumptions, particularly regarding the angular momentum of the moon in orbit and the use of the parallel axis theorem.

Discussion Status

There is an ongoing exploration of the components of angular momentum and how to calculate torque due to changes in the Earth's rotation period. Some participants have provided guidance on using relationships between angular velocity and torque, while others are questioning the assumptions and methods being applied.

Contextual Notes

Participants note the complexity of the problem, particularly in relation to the assumptions about circular orbits and the parallel nature of angular momentum vectors, which may not hold true in reality. There is also a mention of the rate at which the Earth's day is lengthening, which adds to the discussion of torque and angular acceleration.

freek
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The Earth has a rotational period of 23 hours, 56 minutes. The moon has a rotational period of 27.3 days and an orbital period of 27.3 days. The moon has a radius of 1.74 x10^6 m, an orbital radius of 3.82 x10^8 m, and a mass of 7.36 x10^22 kg. The Earth has a radius of 6.37 x10^6 m and a mass of 5.98 x10^24 kg. Assume that the moon has a circular orbit around the Earth and that the three angular angular momentum vectors are parallel (which isn't really the case).

a) calculate the angular momentum of the Earth-moon system. All of the rotations are counterclockwise.

i used the relation T=2pi/omega to solve for omega for both Earth and the moon. assuming both the Earth and the moon are solid spheres, I=.4MR^2. then i used L=I times omega to get L for both the Earth and the moon. and then adding Earth and moon's L's gives me the L for the system. right?

b) If, due to torques internal to the Earth-mmon system, the Earth's day is being lengthened by the rate of 1.48 ms/century, calculate the average torque exerted on the Earth by the moon.

since T is increasing, Earth's angular velocity has to be decreasing. but how do i go about finding the torque? rFsin theta? dL/dt ?

i'm hoping someone can help me get a good start. thanks.
 
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There are contributions to the total angular momentum from both the rotation of each object about its own axis and rotation of both about a common axis (where the center of mass lies). You have to take both into account.

For the second problem, you can find dL/dt from the information provided:

[tex]\tau = I \alpha = I \frac {d \omega}{dt} = \frac {dL}{dt}[/tex]

where [itex]I[/itex] presumably remains the same.
 
freek said:
a) calculate the angular momentum of the Earth-moon system. All of the rotations are counterclockwise.

i used the relation T=2pi/omega to solve for omega for both Earth and the moon. assuming both the Earth and the moon are solid spheres, I=.4MR^2. then i used L=I times omega to get L for both the Earth and the moon. and then adding Earth and moon's L's gives me the L for the system. right?
So far, so good. But don't forget the angular momentum of the moon orbiting the earth.

b) If, due to torques internal to the Earth-mmon system, the Earth's day is being lengthened by the rate of 1.48 ms/century, calculate the average torque exerted on the Earth by the moon.

since T is increasing, Earth's angular velocity has to be decreasing. but how do i go about finding the torque? rFsin theta? dL/dt ?
Figure out the angular acceleration, then use Newton's 2nd law: [itex]\tau = I \alpha[/itex].
 
so, there's four partial angular momentums that make up the total angular momentum of the system:
1 and 2- the Earth and the moon rotating about their own axises.
3 and 4- rotation of both about a common axis that goes through the center of mass for the system (the moon orbiting around the earth).

and to find the I's for the moon and the Earth rotating about that common axis, i have to use the parallel axis theorem. right? I'm just thinking out loud cos the concepts here are more abstract that what I'm used to previously. :-]

and for the second part, how would i figure out the angular acceleration? thanks for the replies.
 
Angular acceleration = change in angular velocity per unit time!

You're given the rate of change of the period so you just need to relate the period to the angular velocity.
 
freek said:
so, there's four partial angular momentums that make up the total angular momentum of the system:
1 and 2- the Earth and the moon rotating about their own axises.
3 and 4- rotation of both about a common axis that goes through the center of mass for the system (the moon orbiting around the earth).
Tide is, of course, correct (as usual :smile: ) about the moon and Earth orbiting about their common center of mass. However, you are asked to treat the simpler case of the moon having a circular orbit around the earth:
"Assume that the moon has a circular orbit around the Earth and that the three angular momentum vectors are parallel (which isn't really the case)."​
 

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