How Does the Doppler Shift Affect Light When Approaching a Source?

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SUMMARY

The discussion confirms that the relativistic Doppler effect applies when moving towards a light source, described by the formula ν = ν₀ √{(1 + v/c)/(1 - v/c)}, where v represents the relative speed between the source and observer. The formula accounts for two primary scenarios: the observer approaching the source and the source approaching the observer. Additionally, the effect is referred to as the "Doppler-Fizeau effect," acknowledging Hippolyte Fizeau's contributions to measuring the speed of light. The conversation emphasizes the distinction between light and sound wave behavior in relation to Doppler shifts.

PREREQUISITES
  • Understanding of the relativistic Doppler effect
  • Familiarity with the formula ν = ν₀ √{(1 + v/c)/(1 - v/c)}
  • Basic knowledge of light and sound wave behavior
  • Awareness of historical figures in physics, specifically Doppler and Fizeau
NEXT STEPS
  • Research the applications of the relativistic Doppler effect in astrophysics
  • Explore the differences between the Doppler effect for sound and light
  • Study the historical context and experiments conducted by Hippolyte Fizeau
  • Learn about the implications of the Doppler-Fizeau effect in modern physics
USEFUL FOR

Physicists, astronomy enthusiasts, and students studying wave phenomena, particularly those interested in the behavior of light and the implications of relativistic effects.

daveed
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do you get a doppler shift when your moving towards a light source? like, i know light gets redshifted with expanding space and gravity, but if light always approaches you at the same speed, how would frequency change there?
 
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daveed said:
do you get a doppler shift when your moving towards a light source?
Absolutely. The relativistic Doppler effect is this:
[tex]\nu = \nu_0 \sqrt{(1 + v/c)/(1 - v/c)}[/tex]
Where v is the relative speed of source and observer. If the source is approaching the observer, v is positive.
 
Doc Al said:
Absolutely. The relativistic Doppler effect is this:
[tex]\nu = \nu_0 \sqrt{(1 + v/c)/(1 - v/c)}[/tex]
Where v is the relative speed of source and observer. If the source is approaching the observer, v is positive.

The formula that Doc gave u is to be used,in all 4 possible cases:u're approaching the light sourse,the light source is approaching u,u're going away from the light source,the light source is going away from u.
It maight be silly to think about 4 possible cases,when there are actually 2.Yes,there are only 2,but in the case of light.Try to apply classical kinematics to sound waves,and u'll find 4 different formulas for each of the cases.Actually 2 formulas,once u've gotten the one,let's say,the sound wave's approaching u,change the sign of the speed in the formula gotten and u'll find the case in which the sound wave is moving away from u.

EDIT:And it's called (for light,that is) "Doppler-Fizeau effect".Doppler discovered it for the sound waves,bu Hippolyte Fizeau (one of the ones who measured the speed of light accuretely) who discovered it for light.
 
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