
#1
Dec2811, 08:17 PM

P: 366

1. The problem statement, all variables and given/known data
Given x=y^2, x=1 what is the area of the solid when the area between the two curves is rotated about x=1. 3. The attempt at a solution I attached my solution and according to the answer key my area formula (pipi*y^4) is wrong. Instead they have pi*(1y^2)^2. Can anyone explain why my area formula is wrong? I thought that it was the area of the upper boundary curve minus the area of the lower boundary curve... 



#2
Dec2811, 08:30 PM

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