Kepler's 2nd Law: Relation of dA/dt to L

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Discussion Overview

The discussion focuses on the relationship between the rate of change of area swept out by a celestial body (dA/dt) and angular momentum (L) in the context of orbital dynamics. Participants explore the mathematical expressions and physical interpretations involved, including the conditions under which certain relationships hold true.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants propose that dA/dt can be expressed as L/(2m) and question how this relates to the vector nature of L compared to the scalar nature of H.
  • Others argue that if m is constant and r x v is constant, then dA/dt should also be constant, suggesting no problem exists in the relationship.
  • One participant questions whether it is correct to equate |L/(2m)| with rv/2, noting that r and v are not always perpendicular, which complicates the relationship.
  • Another participant clarifies that r and v being perpendicular only applies in specific cases, such as circular orbits or at specific points in elliptical orbits (apoapsis or periapsis).
  • There is a correction regarding the interpretation of the cross product, emphasizing that r and v are not always perpendicular, and that the calculation of dA/dt requires using the perpendicular component of the velocity.

Areas of Agreement / Disagreement

Participants express differing views on the conditions under which the relationships hold, particularly regarding the perpendicularity of r and v. The discussion remains unresolved, with multiple competing interpretations of the mathematical relationships involved.

Contextual Notes

Participants note that definitions of variables may vary, leading to potential confusion. The discussion highlights the importance of understanding the conditions under which certain mathematical expressions are valid, particularly in non-circular orbits.

StephenPrivitera
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d2A/dt2=0
or
dA/dt=k=rv/2

L=r x p
L/m=r x v
L/(2m)=(r x v)/2

How does dA/dt relate to L?
In a certain book, it says dA/dt=H/2 where H=L/m=rv
but L is a vector and H is not.
 
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dA/dt = L/(2m) = constant

So where's the problem?
m is a constant; r x v is constant.:wink:
 
L is a vector. So is dA/dt=L/(2m) where L=|L|?
Besides L/(2m)=(1/2)(r x v). Is it correct to say
|L/(2m)|=(1/2)|r|*|v|=rv/2=dA/dt?

edit:
Sorry, found the problem. |r x v|=RVsinA and since r and v are always perpendicular. |r|*|v|=RVsinpi/2=RV
So, |L/(2m)|=(1/2)|r|*|v|=rv/2=dA/dt
Right?

edit:
"since r and v are always perpendicular"
but wouldn't that only work for circular orbits?
 
Last edited:
I don't have my orbital dynamics book on me and some of your variables are using different characters than I'm used to seeing (I'm using Vallado).

What are you defining L , H, and m to be?

r and v are usually _not_ perpendicular. The only cases where they are, are either a) circular orbit or b) sat. is at apoapsis or periapsis.
 
Originally posted by StephenPrivitera


edit:
Sorry, found the problem. |r x v|=RVsinA and since r and v are always perpendicular.
Right?

Wrong; you are correct that it is the cross product; but r and v are not always perpendicular.
r x v does NOT mean v is always perpendicular to r!
By taking the cross product you are, in effect, by definition, taking the perpendicular component of v. The calculation requires using the perpendicular component of the velocity.

edit:
"since r and v are always perpendicular"
but wouldn't that only work for circular orbits?

Correct,Stephen, the orbit would be circular IF and only if v were always perpendicular to r; but it is not.
However, inspite of that, we still always use the perpendicular component of v FOR THE PURPOSE OF CALCULATING dA/dt.
This is necessary because L is defined in the same manner, that is, by taking the perpendicular component of the tangental orbital velocity. L= (r x mv)= (r)*(m)*(v)sin@

Did that make sense??
Creator :wink:
 
Last edited:

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