# 3D stress -strain relationship

by Ronankeating
Tags: relationship, strain, stress
 P: 64 εHi, Based on that hoary schematic cube representation in 3D for stress-strain relationship. Stress tensor {σxx, σyy, σzz, σxy, σyz, σzx} and strain tensors {εxx, εyy, εzz, εxy, εyz, εzx} can be written interchangably. Let's suppose that σzz=σzx=σzy=0 then the reamining terms are written in matrix form then how that E/(1-v2) coefficient is emerging. At first sight, is seems that its very simple to express it by multipliers but couldn't figured out . Any help please,
 P: 5,462 You are missing the off diagonal relationships in your tensor.
 P: 5,462 The relationships betwenn stress and strain are $$\begin{array}{l} {\varepsilon _x} = \frac{1}{E}\left[ {{\sigma _x} - \nu ({\sigma _y} + {\sigma _z}} \right] \\ {\varepsilon _y} = \frac{1}{E}\left[ {{\sigma _y} - \nu ({\sigma _x} + {\sigma _z}} \right] \\ {\varepsilon _z} = \frac{1}{E}\left[ {{\sigma _z} - \nu ({\sigma _x} + {\sigma _y}} \right] \\ {\gamma _{xy}} = \frac{1}{G}{\tau _{xy}} \\ {\gamma _{yz}} = \frac{1}{G}{\tau _{yz}} \\ {\gamma _{xz}} = \frac{1}{G}{\tau _{xz}} \\ \end{array}$$ Written in matrix form this becomes $$\varepsilon = C\sigma$$ where C is the matrix $$C = \frac{1}{E}\left[ {\begin{array}{*{20}{c}} 1 & { - v} & { - v} & 0 & 0 & 0 \\ { - v} & 1 & { - v} & 0 & 0 & 0 \\ { - v} & { - v} & 1 & 0 & 0 & 0 \\ 0 & 0 & 0 & {\frac{E}{G}} & 0 & 0 \\ 0 & 0 & 0 & 0 & {\frac{E}{G}} & 0 \\ 0 & 0 & 0 & 0 & 0 & {\frac{E}{G}} \\ \end{array}} \right]$$
P: 5,462
3D stress -strain relationship

 (But I'm intending to write stress as function of strain)
you do this by solving (inverting) my matrix equation

ε=Cσ

this is possible and leads to

$$\begin{array}{l} {\sigma _x} = A\left[ {{\varepsilon _x} + B\left( {{\varepsilon _y} + {\varepsilon _z}} \right)} \right] \\ {\sigma _y} = A\left[ {{\varepsilon _y} + B\left( {{\varepsilon _x} + {\varepsilon _z}} \right)} \right] \\ {\sigma _z} = A\left[ {{\varepsilon _z} + B\left( {{\varepsilon _x} + {\varepsilon _y}} \right)} \right] \\ {\tau _{xy}} = G{\gamma _{xy}} \\ {\tau _{yz}} = G{\gamma _{yz}} \\ {\tau _{xz}} = G{\gamma _{xz}} \\ \end{array}$$

Also

$$\begin{array}{l} G = \frac{E}{{2\left( {1 + \nu } \right)}} \\ A = E\frac{{\left( {1 - \nu } \right)}}{{\left( {1 + \nu } \right)\left( {1 - 2\nu } \right)}} \\ B = \frac{\nu }{{\left( {1 - v} \right)}} \\ \end{array}$$

As regards to the LaTex this site uses for formulae, I am seriously deficient in latex lore so I use MathType and copy/paste.
I wouldn't recommend MT, however as it is too expensive for what it is and does not allow the inclusion of images.
 P: 5,462 There seems to be a missing post, however to complete a matrix expression for stress in terms of strain is $$\sigma = D\varepsilon$$ where D is the matrix $$D = A\left[ {\begin{array}{*{20}{c}} 1 & B & B & 0 & 0 & 0 \\ B & 1 & B & 0 & 0 & 0 \\ B & B & 1 & 0 & 0 & 0 \\ 0 & 0 & 0 & {\frac{G}{A}} & 0 & 0 \\ 0 & 0 & 0 & 0 & {\frac{G}{A}} & 0 \\ 0 & 0 & 0 & 0 & 0 & {\frac{G}{A}} \\ \end{array}} \right]$$ A and B have the same meaning as before

 Related Discussions Mechanical Engineering 0 Mechanical Engineering 2 Classical Physics 1 Introductory Physics Homework 20 Engineering, Comp Sci, & Technology Homework 2