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How to Calculate Cube Root Of 24 digit number?

 
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Jan22-12, 12:19 AM   #1
 

How to Calculate Cube Root Of 24 digit number?


Hello Friends,
I have a question of calculating a cube root of large number like 24 digit number.
I calculated by means of Wolfram but I want to try it myself on paper. Is there a method such as Calculus or Algebraic to find the cube root?
Thank you.
P.S. I want to use the method for several other numbers.
 
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Jan22-12, 12:31 AM   #2
 
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Factorize the number into simpler roots and multiply them.
Solve for the prime numbers using the Newton-Raphson algorithm.

Do you want only real roots or do you want the complex ones as well?

note:
http://mathforum.org/library/drmath/view/65174.html
http://www.mathpath.org/Algor/cubero....cube.root.htm
... note: this last one is probably what you want.
 
Jan22-12, 12:38 AM   #3
 
Well the number is : x^3= 133737775549834923406792. So I wish to find out the 'x'.
And x is a positive integer. So I only want the real part here. And the real part only exists.
thanks Simon Bridge. :)
 
Jan22-12, 12:39 AM   #4
 

How to Calculate Cube Root Of 24 digit number?


Well the number is : x^3= 133737775549834923406792. So I wish to find out the 'x'.
And x is a positive integer. So I only want the real part here. And the real part only exists.
thanks Simon Bridge. :)
 
Jan22-12, 12:57 AM   #5
 
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You can try an algorithm like this: http://www.mathpath.org/Algor/cubero....cube.root.htm
 
Jan22-12, 01:00 AM   #6
 
^ Just searching on the same site. :)
Thanks.
 
Jan22-12, 01:07 AM   #7
 
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second link post #2. well done.
that cube is very leet :)
 
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