How to Find c for Given Joint PDF?

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SUMMARY

The discussion focuses on determining the constant \( c \) for the joint probability density function (PDF) \( f_{XY}(x, y) = c(y + x)y \) defined for \( 0 < x < 1 \) and \( 0 < y < 1 \). Participants clarify that to find \( c \), one must integrate the joint PDF over the specified range and set the result equal to 1, ensuring the total probability is normalized. The integration limits are from 0 to 1 for both variables, confirming that the total probability must equal 1. This method is essential for validating the joint PDF's correctness.

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semidevil
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so X and Y have joing pdf f X Y(x, y) = 1/2 for 0 < y < x < 2, and 0 otherwise.

find P(0< Y < 2/5 | X = 3/4)

first, I don't understand how to read the function. So the function is equal to 1/2 when 0 < y < x < 2. And it is equal 0 otherwise.

So I need to find probability Y is between 0 and 2/5, given that X = 3/4? is that what it is asking?

I think this has to do with integration, but what am I integrating? It's a single integeral right? and what do I do w/ the X = 3/4 part?


actually, I got it...so no need for that.

but this one. so f X Y (x,y) = c(y + x)y for 0<x<1 and 0<y<1.

I need to find c.

So I found the marginals, and what do I do to find c? am I suppose to put it against something?
 
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The total probability may be equal 1, right?
 
You don't need to find the marginals. The integral of the function from -infinity to infinity for both x and y (which is the same as the integral from 0 to 1 for both x and y in this case) equals 1, and you just solve for c.
 

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