Converting velocity/time graph to acceleration/time

Thread starter NINHARDCOREFAN
Start date Sep 11, 2003
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SUMMARY

The discussion focuses on converting a velocity/time graph into an acceleration/time graph by analyzing the slope of the velocity graph. It is established that acceleration is defined as the rate of change of velocity over time. In the example provided, a steady increase in velocity from 0 m/sec at t=0 to 4 m/sec at t=2 results in a constant acceleration of 2 m/sec², confirming that the slope of the graph directly represents acceleration.

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Understanding of basic kinematics concepts
Familiarity with graph interpretation
Knowledge of slope calculations
Basic calculus principles related to derivatives

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Sep 11, 2003

NINHARDCOREFAN

How do I do that?

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Sep 11, 2003

enigma

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acceleration is the rate of change of time. The rate of change is found by looking at the slope of the graph.

So if velocity is increasing steadily from 0 m/sec at t=0 to 4 m/sec at t=2, then the slope is a constant 2 m/sec². The slope corresponds to a constant acceleration of 2.