Comparing Forces and Power in a Pulley System: Help with Multiple Choice

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Homework Help Overview

The problem involves two identical blocks being lifted at constant velocity by ropes over frictionless pulleys, with one block being raised at twice the speed of the other. Participants are tasked with determining the correct relationships between the forces and power for each block based on multiple-choice options.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the implications of constant velocity on force and power, questioning how speed affects power and whether equal velocities imply equal forces. Some participants express differing opinions on the correct answer, citing reasoning related to equilibrium and power calculations.

Discussion Status

The discussion is active, with participants sharing their thoughts on the multiple-choice options and providing reasoning for their choices. There is no clear consensus, as different interpretations of the problem and its implications are being explored.

Contextual Notes

Some participants note the absence of a diagram, which limits their ability to visualize the pulley arrangement. The discussion also reflects on the assumptions related to constant velocity and equilibrium in the context of the problem.

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Help please--multiple choice

Two identical blocks are lifted at constant velocity by ropes that run over frictionless pulleys, as shown in the diagram. Block B is raised twice as fast as Block A. The magnitudes of the forces are respectively FA and FB, while the power supplied is respectively PA and PB. Which statement is correct?

a. FB = FA; PB = PA.
b. FB = FA; PB = 2 PA.
c. FB = 2 FA; PB = PA.
d. FB = 2 FA; PB = 2 PA.
e. PA = FA; PB = FB.
 
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I believe it's d).Tell us what u think and bring arguments.That's the only way to check and (probably) correct your reasoning.

Daniel.
 
Phyzix said:
Two identical blocks are lifted at constant velocity by ropes that run over frictionless pulleys, as shown in the diagram. Block B is raised twice as fast as Block A. The magnitudes of the forces are respectively FA and FB, while the power supplied is respectively PA and PB. Which statement is correct?
Since you did not supply the diagram, we can only guess as to the arrangement of the pulleys. Assuming that both ropes run over single pulleys...

What does "constant velocity" tell you about the force needed? How does power depend upon speed?
 
dextercioby said:
I believe it's d).Tell us what u think and bring arguments.That's the only way to check and (probably) correct your reasoning.

Daniel.

d?? I think it's a) - because it is at a constant velocity.
 
futb0l said:
d?? I think it's a) - because it is at a constant velocity.

At equal velocities but different times,does it mean the same force??

Daniel.
 
futb0l said:
d?? I think it's a) - because it is at a constant velocity.
Both d) and a) are half right. :smile: But more important than the answer is the reasoning behind it (as Daniel would say).
 
Ooops - I meant b)... since power is F*v since b has 2v, then the power of b will be twice as much as a. Since it is at equillibrium then Fa = Fb.
 
I agree: b) is the correct answer.
 
Me too. Distance traveled by 1s : Distance traveled by 1s=1:s
Hence PA: PB=1:2
 

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