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Integration questionby cycling4life
Tags: integration 
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#1
Jan3112, 09:49 PM

P: 7

In part of a derivation they have, Integrate dx/(1x) = (1aW)^(1/2) dW
I get ln(1x) = (2/3a)*(1aW)^(3/2) but they say it's ln(1/(1X)) = (2/3a)((1(1AW)^(3/2)) Can anyone tell me how they get that extra "1"? 


#2
Feb112, 02:43 AM

P: 761

ln(1x) = (2/3a)*(1aW)^(3/2) + Contant



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