Register to reply 
Integration questionby cycling4life
Tags: integration 
Share this thread: 
#1
Jan3112, 09:49 PM

P: 7

In part of a derivation they have, Integrate dx/(1x) = (1aW)^(1/2) dW
I get ln(1x) = (2/3a)*(1aW)^(3/2) but they say it's ln(1/(1X)) = (2/3a)((1(1AW)^(3/2)) Can anyone tell me how they get that extra "1"? 


#2
Feb112, 02:43 AM

P: 756

ln(1x) = (2/3a)*(1aW)^(3/2) + Contant



Register to reply 
Related Discussions  
Integration question  Calculus & Beyond Homework  2  
Question of integration..  Calculus  4  
Question about Integration  Calculus  21  
Question arrising from integration homework (advanced integration i guess?)  Calculus  9  
Integration question  Introductory Physics Homework  1 