Instantaneous Velocity: drag racing problemby chinnie15 Tags: drag, instantaneous, racing, velocity 

#1
Feb412, 04:25 PM

P: 29

The figure shows a graph of actual positionversustime data for a particular type of drag racer known as a "funny car."
Estimate the car's velocity at 2.0s Equation: v = m/s I thought I knew how to solve this, and I made a tangent line at the curve and 2s, and when I do the slope at different points on the tangent I keep getting somewhere in the field of 50m/s. However, it keeps telling me I'm wrong. What should I be doing differently? Thank you for your help! 



#2
Feb412, 07:19 PM

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your answer looks ok to me. what keeps telling you that its wrong?




#3
Feb412, 08:25 PM

P: 29

The program I have to use for class (Mastering Physics). It says express the answer with proper units and 2 significant figures, but whether I put in 50m/s or 50.0 m/s, it's still saying it's incorrect?




#4
Feb412, 11:17 PM

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Instantaneous Velocity: drag racing problemHave you tried entering scientific notation? 



#5
Feb512, 12:06 AM

P: 29

Thanks!
67 m/s ended up being the correct answer. I redrew my tangent line, and took another slope and I ended up getting an answer extremely close to that, so my tangent line was just off before. Only problem is now, I have to do this again for t=4s. I have, once again, exhausted most of my attempts trying to get the correct answer. What am I doing wrong?? Here is my tangent line for t=4: I am getting a slope around 80m/s. Is my tangent line really that off? Thank you so much for your help! 



#6
Feb512, 12:32 AM

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#7
Feb512, 12:44 AM

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I know that. :) This is for the second question, which is for the velocity at t = 4s. The first question was t = 2s. I got that answer for t = 2s correct now, it was 67 m/s. But now I can't get the correct answer for t = 4s.




#8
Feb512, 12:50 AM

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It's much more like ≈250/2 = 125 


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