
#1
Feb712, 07:59 PM

P: 99

If you integrate
1/(1y)dy why do you end up with a negative in front of your answer ln1y+c 



#2
Feb712, 08:01 PM

PF Gold
P: 1,930

Because using usubstitution, we get this:
u = 1  y, du =  dy And so... [tex]\int \frac{1}{1y} dy =  \int \frac{1}{u} du[/tex] Integrating the righthand side, we get  lnu + C, or  ln1y + C. 



#3
Feb712, 10:47 PM

P: 99

gotcha



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