Calculate the Height of a High Rise Building with Trig Word Problem

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Homework Help Overview

The problem involves calculating the height of a high-rise building using trigonometric principles. Jennie stands 30 m away from the building, and the angle of elevation to the top is given as 70°, with her eye level at 1.8 m above the ground.

Discussion Character

  • Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of the tangent function to relate the height of the building to the distance from it. There are attempts to calculate the height based on the angle of elevation and the distance, with some questioning the logical consistency of the initial equations presented.

Discussion Status

Multiple participants have engaged in calculations, arriving at similar numerical results for the height of the building. However, there are also discussions about the validity of the equations used and the assumptions regarding eye level. The conversation includes some light-hearted commentary on height perceptions.

Contextual Notes

Some participants express personal feelings about height differences, which may influence their perspectives on the problem. There is a mix of serious mathematical discussion and casual banter regarding height and personal experiences.

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Jennie stands 30 m from the base of a high rise building. The angle of elevation from her eyes to the top of the tower is 70°. How high is the tower if her eyes are 1.8 m above the ground?

Is the answer to this 82.42 m + 1.8m=84.22 m?
 
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tan(70) = x/30 = 82.42

82.42 + 1.8 = 84.22

Yup
 
phreak said:
tan(70) = x/30 = 82.42

82.42 + 1.8 = 84.22

Yup

Your first equation doensn't make any logical sense...
[tex]\tan 70°=\frac{h}{30}\sim 2.747 \Rightarrow h\sim 2.747\cdot 30=82.415m[/tex]
Total height:approx.84.2 m.

Daniel.

PS.1.80m to her eyes,almost 1.90m in all:that's a giant *****...! :-p
 
aisha said:
Jennie stands 30 m from the base of a high rise building. The angle of elevation from her eyes to the top of the tower is 70°. How high is the tower if her eyes are 1.8 m above the ground?

Is the answer to this 82.42 m + 1.8m=84.22 m?

[tex]Tan \Psi = \frac {Opp}{Adj}[/tex]

[tex]Tan 70 = \frac {x}{30}[/tex]

[tex]x = Tan70 \times 30[/tex]

[tex]x = 82.42[/tex]

Then add 1.8m becaue of her eye level:

[tex]y = 82.42 + 1.8[/tex]

[tex]y = 84.22m[/tex]

Therefore I say you are right in what you originally said.

The Bob (2004 ©)

P.S. Well my eye level is about 1.95m :-p
 
1.9 meters is not a giant...
its about 6 feet 3 inches...
im 6' exactly
 
qweretyq said:
1.9 meters is not a giant...
its about 6 feet 3 inches...
im 6' exactly
If you check my post above I said that my eye level was about 1.95m (probably more now :-p) and I am not a giant. Just rather tall.

The Bob (2004 ©)
 
Since I'm only 1.71,i feel quite uncomfortable when a lady next to me is towering 20 cm more...Bob,if u were near a girl at 2.15,u'd feel the same way... :-p

Daniel.
 
1.90 meters is very tall for a girl, too tall, in fact. I'd say that she's "deformed."
 
Last edited:
dextercioby said:
Since I'm only 1.71,i feel quite uncomfortable when a lady next to me is towering 20 cm more...Bob,if u were near a girl at 2.15,u'd feel the same way... :-p
I most likely would but you find a female 2.15m :-p

I have met a female almost as tall as me, two infact, and you do wonder why or how. Then you think why or how you are that tall as well.

The Bob (2004 ©)
 
  • #10
iodmys said:
I'd say that she's "deformed."
A little harsh really.

The Bob (2004 ©)
 

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