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Problem about an sphere. |
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| Feb29-12, 09:28 PM | #18 |
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Problem about an sphere.
a fraction is a part of a whole, right? So which part of what whole are we looking for?
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| Feb29-12, 09:43 PM | #19 |
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LOL good question. Total KE?? But what is the total kineteci eenrgy here is it KE rot+ KE trans?? so is 1/2mv^2/1/2mv^2+1/5mv^2?
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| Feb29-12, 09:44 PM | #20 |
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Ke rot /KEtotal??? Is it like this 1/2mv^2/1/2mv^2+1/5mv^2?
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| Feb29-12, 09:52 PM | #21 |
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it actually tells you in the question ;)
"What fraction of its kinetic energy is rotational?" in other words: Which part of the total kinetic energy is rotational kinetic energy? Thus, we are looking for the rotational part of the total kinetic energy. if you have [itex]\frac{\frac{1}{2}mv^{2}}{\frac{1}{2}mv^{2}+\frac{1}{5}mv^{2}}[/itex] then what is that representing? |
| Feb29-12, 10:11 PM | #22 |
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a fraction .... but if the m's and v's cancel they give 5/7 not 2/7 i give up.
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| Feb29-12, 10:17 PM | #23 |
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wait! don't give up! we're almost there :D
what I was just asking was what's on top? Is it rotational kinetic energy or tangential kinetic energy? |
| Feb29-12, 10:19 PM | #24 |
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KE rot
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| Feb29-12, 10:20 PM | #25 |
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is [itex]\frac{1}{2}mv^{2}[/itex] the rotational kinetic energy?
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| Feb29-12, 10:36 PM | #26 |
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ahh tangential is 1/2mv^2 my bad KE rot is 1/5Iw^2? ARRGHHH JFC!!! ROFLMAO!!! I though KE rot was 1/2mv^2 when is 1/5mv^2 now it does give 2/7!! :P Thank you so much for your patients dude!!!
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| Feb29-12, 10:40 PM | #27 |
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no problem, glad I could help :)
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