Question regarding Binomial expansion.

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  • Thread starter Thread starter Sanosuke Sagara
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    Binomial Expansion
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The discussion focuses on solving the equation \(\frac{1-x}{1+x}=\frac{19}{21}\) to find the value of \(x\) under the condition that \(x^3\) is ignorable. The fourth root of \(\frac{19}{21}\) is expressed as \((\frac{19}{21})^{1/4}\). The polynomial formula with \(n=1/4\) is utilized to achieve the desired approximation. The participants confirm that the problem is now understood and solvable.

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Sanosuke Sagara
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I have my question and my problem in the attachment that followed.
 

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By "fourth root of 19/21", they mean the quantity [itex](19/21)^{1/4}[/itex].

Like in your other question, you would like to find the x meeting the condition "x^3 is ignorable" and such that

[tex]\frac{1-x}{1+x}=\frac{19}{21}[/tex]

You will find that x easily by solving this last equation for x.

Then, with n=1/4, your polynomial formula gives you the wished approximation.
 
Thanks for your help.I think I now can understand with what the question want.
 

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