Question regarding Binomial expansion.

Sanosuke Sagara

I have my question and my problem in the attachment that followed.

quasar987

By "fourth root of 19/21", they mean the quantity [itex](19/21)^{1/4}[/itex].

Like in your other question, you would like to find the x meeting the condition "x^3 is ignorable" and such that

[tex]\frac{1-x}{1+x}=\frac{19}{21}[/tex]

You will find that x easily by solving this last equation for x.

Then, with n=1/4, your polynomial formula gives you the wished approximation.

Sanosuke Sagara

Thanks for your help.I think I now can understand with what the question want.

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quasar987 Recognitions: Gold Member Homework Help Science Advisor	By "fourth root of 19/21", they mean the quantity [itex](19/21)^{1/4}[/itex]. Like in your other question, you would like to find the x meeting the condition "x^3 is ignorable" and such that [tex]\frac{1-x}{1+x}=\frac{19}{21}[/tex] You will find that x easily by solving this last equation for x. Then, with n=1/4, your polynomial formula gives you the wished approximation.

Sanosuke Sagara	Thanks for your help.I think I now can understand with what the question want.