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Christmas tree light

 
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Mar1-12, 01:24 PM   #1
 

Christmas tree light


Forgive the sloppy use of math and inability to produce an image. I noticed this last christmas.

If you have a fairy light ( or perhaps any LED etc), and shine it normal to a surface, you see a circle. If you place the light flat on the surface you see a curve - to me the fairy lights' curve looks like a hyperbola.

Does this have any relation to the equation of a circle:
[tex]x^2+y^2=const.[/tex]
And Hyperbola:
[tex]x^2-y^2=const.[/tex]
And subsitution for 90 degrees rotation? :
[tex]y\rightarrow iy[/tex]

If so, how does this even work? The experiment is all in real space. If not, is this just sloppy use of math? Any significance?

Thanks
 
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Mar1-12, 02:43 PM   #2
 
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Hi Livethefire!

If the light comes out in a cone,

then the shape will be the intersection of a cone with a plane …
in other words, a conic section
 
Mar1-12, 02:49 PM   #3
 
Ah yes!

But is there any relevance or justified motivation to present such a thing by substituting "iy" in a circular equation?
 
Mar1-12, 02:54 PM   #4
 
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Christmas tree light


not following you
 
Mar1-12, 02:58 PM   #5
 
What I was saying in post #1 was to sub iy for y in the first equation you get the second. In other words, rotating the axis 90 degrees changes the view from a circle to a hyperbola.

Sometimes i is used as a 90 degree operator, yet I think my reasoning is unsound, thus i am asking here for insight.
 
Mar1-12, 03:21 PM   #6
 
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if the cone has semiangle λ along the z-axis, then its equation is

z2 = (x2 + y2)tan2λ,

so a plane z = xtanθ + c cuts it at x2(tan2λ - tan2θ) - 2cxtanθ + y2tan2λ = c2,

which is an ellipse or hyperbola according to whether λ is greater or less than θ

(but i don't see where i comes into it)
 
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