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1st order ivp |
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| Mar7-12, 05:15 PM | #1 |
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1st order ivp
y' = x
x' = -5y-4x y(0) = 1 x(0) = 0 after finding the general solution as shown here http://www.wolframalpha.com/input/?i...%27+%3D+-5y-4x how do you go about applying the initial values and finding the complete solution? |
| Mar7-12, 05:24 PM | #2 |
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Your general solution should have two undetermined coefficients. Substitute 0 for t, set x= 0, y= 1 and you will have two equations to solve for the two coefficients.
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| Mar7-12, 10:39 PM | #3 |
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actually I don't think wolfram alpha has done the correct thing in making x and y a function of t as there's no mention of another variable in the original equations. What would you do when they aren't functions of t?
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| Mar8-12, 07:13 AM | #4 |
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1st order ivp
You can call the independent variable whatever you want! What did you mean by x' and y'? I assumed the primes were derivatives. With respect to what variable?
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