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1st order ivpby Ry122
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#1
Mar712, 05:15 PM

P: 519

y' = x
x' = 5y4x y(0) = 1 x(0) = 0 after finding the general solution as shown here http://www.wolframalpha.com/input/?i...%27+%3D+5y4x how do you go about applying the initial values and finding the complete solution? 


#2
Mar712, 05:24 PM

Math
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PF Gold
P: 39,340

Your general solution should have two undetermined coefficients. Substitute 0 for t, set x= 0, y= 1 and you will have two equations to solve for the two coefficients.



#3
Mar712, 10:39 PM

P: 519

actually I don't think wolfram alpha has done the correct thing in making x and y a function of t as there's no mention of another variable in the original equations. What would you do when they aren't functions of t?



#4
Mar812, 07:13 AM

Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 39,340

1st order ivp
You can call the independent variable whatever you want! What did you mean by x' and y'? I assumed the primes were derivatives. With respect to what variable?



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