Register to reply 
1st order ivpby Ry122
Tags: order 
Share this thread: 
#1
Mar712, 05:15 PM

P: 517

y' = x
x' = 5y4x y(0) = 1 x(0) = 0 after finding the general solution as shown here http://www.wolframalpha.com/input/?i...%27+%3D+5y4x how do you go about applying the initial values and finding the complete solution? 


#2
Mar712, 05:24 PM

Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 39,497

Your general solution should have two undetermined coefficients. Substitute 0 for t, set x= 0, y= 1 and you will have two equations to solve for the two coefficients.



#3
Mar712, 10:39 PM

P: 517

actually I don't think wolfram alpha has done the correct thing in making x and y a function of t as there's no mention of another variable in the original equations. What would you do when they aren't functions of t?



#4
Mar812, 07:13 AM

Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 39,497

1st order ivp
You can call the independent variable whatever you want! What did you mean by x' and y'? I assumed the primes were derivatives. With respect to what variable?



Register to reply 
Related Discussions  
MultiVariable Second Order Taylor Series Expansion, Ignoring SOME second order terms  Differential Equations  6  
Find all groups of order 9, order 10, and order 11  Calculus & Beyond Homework  10  
Binary relations: weak order, strict partial order, equivalence  Calculus & Beyond Homework  0  
Reducing third order ODE to a system of first order equs + 4th order rungekutta  Differential Equations  1  
Reducing third order ODE to a system of first order equs + 4th order rungekutta  Calculus & Beyond Homework  0 