The Force of Gravity: Understanding Acceleration of 2-Kg Rocks

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Homework Help Overview

The discussion revolves around the force of gravity acting on two rocks of different masses, specifically a 2-kg rock and a 1-kg rock. Participants are exploring the relationship between mass, gravitational force, and acceleration.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are questioning why the 2-kg rock does not fall with twice the acceleration compared to the 1-kg rock, despite the gravitational force being greater on the heavier rock. Some are attempting to apply Newton's second law (F=ma) to analyze the situation.

Discussion Status

There is an ongoing exploration of the relationship between mass and acceleration under gravity. Some participants are providing mathematical reasoning to support their claims, while others are seeking clarification on the concepts involved. No explicit consensus has been reached yet.

Contextual Notes

Participants are working within the framework of Newtonian physics and are discussing the implications of gravitational force and mass on acceleration. There may be assumptions about the uniformity of gravitational acceleration that are being questioned.

Stargate
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The force of gravity is twice as great on a 2-kg rock on a 1-kg rock. Why does the 2-kg rock not fall with twice the acceleration?
 
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Stargate said:
The force of gravity is twice as great on a 2-kg rock on a 1-kg rock. Why does the 2-kg rock not fall with twice the acceleration?


[tex]F=ma[/tex]
If the force is the product between the mass and the acceleration,figure out yourself...

Daniel.
 
They both have the same mass and acceleration! Right?
 
Last edited:
Stargate said:
They both have the same mass and acceleration! Right?

Okay,for the first body write
[tex]G_{1}=m_{1}a_{1}[/tex](1)
And for the second
[tex]G_{2}=m_{2}a_{2}[/tex](2)

Divide (1) through (2)
[tex]\frac{G_{1}}{G_{2}}=\frac{G_{1}a_{1}}{G_{2}a_{2}}[/tex](3)
Use the fact that [itex]G_{1}[/itex] is two times [itex]G_{2}[/itex] and that [itex]m_{1}[/itex] is 2Kg,which is two times the value of [itex]m_{2}[/itex] which is 1Kg.Then
[tex]2=\frac{2a_{1}}{a_{2}} \Rightarrow a_{1}=a_{2}[/tex]

Daniel.
 

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