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Magnetic Force in a Current Carrying Wire |
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| Mar14-12, 09:44 PM | #1 |
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Magnetic Force in a Current Carrying Wire
1. The problem statement, all variables and given/known data
The current in a wire consists of n electrons per unit volume moving with a velocity v. What is the effect on these electrons of the magnetic field set up by the current itself within the wire? What is the force on one electron at a distance r from the centre of the wire? 2. Relevant equations F = QvBsinθ Magnetic field strength at a distance r from the axis of the wire outside the wire = u0I/2∏r 3. The attempt at a solution I know that for part 1, the effect of the magnetic field on the electrons inside the wire will be a radially outward force (taking all electrons to be travelling in straight lines along the wire). Part 2 F will be equal to QvBsin90 = QvB Making the subsitution for B I have F = Qvu0I/2∏r I believe now that I have to make subsitution for I. Which would be 4/3∏a3vne where e is fundamental charge and a is the radius of the wire. This gives: F = (3/8)u0ve2na3r I know that the answer is: F = (1/2)u0v2e2nr I think I'm making a mistake in calculating my current, but I'm not sure. Help Please? Thanks |
| Mar15-12, 12:14 AM | #2 |
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Hi! This is my first time helping someone out so here goes:
To make the substitution for current I, you should use: [itex] I=\int J \bullet da [/itex] where J is the current density, equal to nev in this case. After doing a quick integration you should get the proper current which will give the correct answer for the force. |
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