Help! Exam in one hour! Find equation of plane?


by cjavier
Tags: calculus, lines, plane
cjavier
cjavier is offline
#1
Mar16-12, 10:55 AM
P: 17
Find an equation of the plane containing the two lines?
The lines are:

(x - 2) / -3 = (y + 1) / 2 = (z - 3) / 1 and (x - 8) / -1 = (y + 5) / -2 = (z -1) / 4
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chiro
chiro is offline
#2
Mar16-12, 11:00 AM
P: 4,570
Quote Quote by cjavier View Post
Find an equation of the plane containing the two lines?
The lines are:

(x - 2) / -3 = (y + 1) / 2 = (z - 3) / 1 and (x - 8) / -1 = (y + 5) / -2 = (z -1) / 4
Can you find the direction vector of both lines? What does the cross product of two vectors give us with respect to information about the plane?
cjavier
cjavier is offline
#3
Mar16-12, 11:07 AM
P: 17
Quote Quote by chiro View Post
Can you find the direction vector of both lines? What does the cross product of two vectors give us with respect to information about the plane?
Before I dive in can I clarify, the direction vector of line one is <-3, 2, 1> and line 2 is <-1, -2, 4> and by taking the cross product I find the normal vector of the plane. With this normal vector, I can take a point, either (2, -1, 3) OR (8, -5, 1) and use the normal vector to find the equation of the plane?


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