Feedback characteristics of nonlinear dynamical systemsby Selfluminous Tags: control theory, differential eqns, dynamical systems, nonlinear dynamics 

#1
Mar2012, 10:05 PM

P: 19

Hi everyone, i am not sure if this is the right place to ask this question.
I am trying to understand the following article: A. Lahellec, S. Hallegatte, J.Y. Grandpeix, P. Dumas and S. Blanco, Europhys. Lett. 81, 60001 (2008). In the beginning, it was quite easy to follow: Consider a statespace model driven by some external forcing [itex] \mathbf{h}(t) [/itex]: [itex]\partial_t\mathbf{x}(t)= \mathbf{g}(\mathbf{x}(t),\mathbf{h}(t)) [/itex], [itex]\mathbf{x}(t=0)=\mathbf{x}_0[/itex] (1) where [itex]\mathbf{x}[/itex] is the state space vector. Once a reference trajectory [itex]T^{ref}[/itex] is followed, perturbations to (1) are solutions to the tangent linear system: [itex]\partial_t\delta\mathbf{x}(t)=A(t)\delta\mathbf{x}(t)+B(t)\delta\mathbf {h}(t) [/itex], [itex]t\in\left[0,T\right][/itex] (2) In (2) [itex]\delta\mathbf{x}[/itex] is the deviation of the perturbed system from [itex]T^{ref}[/itex] caused by perturbation [itex]\delta\mathbf{h}(t)[/itex] of the reference forcing function. [itex]A(t)=\partial_x\mathbf{g}(t) [/itex] and B(t)=[itex]\partial_h\mathbf{g}(t)[/itex] are the Jacobian matrices. To create a feedback loop in the system: A scalar variable [itex]\varphi[/itex] is added to the system, with [itex]\varphi = f(x) [/itex] i.e. a function of the state variable. The primitive model (1) is modified to be sensitive to [itex]\varphi[/itex] in such a way that original and modified models are mathematically equivalent: [itex]\partial_t\delta\mathbf{x}(t)=\mathbf{g'}(\mathbf{x}(t),\varphi(t),\mat hbf{h}(t)) =\mathbf{g}(\mathbf{x}(t),\mathbf{h}(t)) [/itex]. A scalar perturbation [itex]u(t)[/itex] is applied to [itex]\varphi[/itex] only: [itex]\varphi (t) = f(x) + u(t)[/itex]. The system will respond to that change within the feedback loop: perturbation [itex]u[/itex] on [itex]\varphi[/itex] [itex]\rightarrow[/itex] selected mechanisms [itex]\rightarrow[/itex] rest of the system [itex]\rightarrow[/itex] response [itex]\delta\varphi [/itex]. The opening of the loop (figure on the left) means preventing the system from responding on [itex]\varphi[/itex]. (From here on i don't understand) Following the preceding procedure, the original tangent system (2) is modified into the following two equations: [itex]\partial_t\delta\mathbf{x}(t)=A^b(t)\delta\mathbf{x}(t)+\leftb(t)\righ t\rangle\delta\varphi(t) [/itex] [itex]\; \; \; \; [/itex] [itex] \delta\varphi(t)=\left\langle c(t)\right\delta\mathbf{x}(t)+u(t) [/itex] (3) The column and row matrices [itex]\leftb(t)\right\rangle = \partial_{\varphi}\mathbf{g'} [/itex] and[itex] \left\langle c(t)\right = \partial_xf [/itex] formalize the feedback loop. For (3) to be equivalent to (2) the equality : [itex]A(t)=A^b(t)+\leftb\right\rangle\left\langle c\right (t) [/itex] (4) must hold. System (3) takes the form of (2) when [itex]\delta\varphi[/itex] has been eliminated. My questions are: 1. How is (2) modified into (3) ? I am not familiar with these notations and i don't get why the term [itex]A^b [/itex] appears and [itex]B(t) [/itex] disappears. O_O 2. Consequently, explain why (4) is the condition for (2) and (3) to be equivalent. 3. It seems like (3) is the equations for closed loop feedback. To open the loop we set [itex] \left\langle c \right[/itex] to 0 and disallow the system perturbation to influence [itex]\varphi[/itex]. Is that correct ? 


Register to reply 
Related Discussions  
Interested in Chaos Theory, Complex Systems, Nonlinear Systems  Academic Guidance  8  
Logistic Dynamical System (discrete dynamical systems)  Calculus & Beyond Homework  0  
Nonlinear dynamical systems  Engineering Systems & Design  0  
Nonlinear Dynamical Systems: Book Suggestions  Differential Equations  0  
GR and Dynamical Systems  Special & General Relativity  7 