Solving a Math Problem: Overcoming a Mental Lapse

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SUMMARY

The discussion focuses on transforming the expression 3(cos²(x)sin²(x)) into the identity sin(2x) = 2sin(x)cos(x). The user seeks assistance in rewriting the formula correctly, utilizing the identity that relates sin²(x)cos²(x) to sin(2x). The transformation involves recognizing that cos²(x)sin²(x) can be expressed as (sin(2x)/2)², leading to a simplified form that aligns with the double angle identity.

PREREQUISITES
  • Understanding of trigonometric identities, specifically the double angle formulas.
  • Familiarity with algebraic manipulation of trigonometric functions.
  • Knowledge of the Pythagorean identity and its applications.
  • Basic calculus concepts, particularly derivatives of trigonometric functions.
NEXT STEPS
  • Study the derivation of the double angle identities for sine and cosine.
  • Practice algebraic manipulation of trigonometric expressions.
  • Explore the application of trigonometric identities in solving complex equations.
  • Learn about the graphical representation of trigonometric functions and their transformations.
USEFUL FOR

Students, educators, and anyone interested in enhancing their understanding of trigonometric identities and algebraic manipulation in mathematics.

derekmohammed
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Hi

I am having a little bit of a mental lapse right now :cry: :zzz: and I was wondering if someone could help me out.

I want to write the formula as

3(cos^2(x)sin^2(x)) to the identity sin2x = 2sinxcosx

Thanks a lot!
 
Last edited:
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Note that:
[tex]\cos^{2}x\sin^{2}x=(\cos{x}\sin{x})^{2}=(\frac{2\cos{x}\sin{x}}{2})^{2}[/tex]
 
Thanks arildno...
 

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