Calculating p/n: Solving for the Ratio of Two Averages in a Mental Lapse

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Homework Help Overview

The discussion revolves around calculating the ratio of two averages related to the scores of two groups of students, specifically focusing on the variables p and n representing the number of students in each group.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to derive the relationship between p and n using the given average scores and expresses confusion about the next steps after establishing the ratio.

Discussion Status

Some participants suggest that the original poster has reached a point where the ratio is established, but without specific values for p or n, further calculation may not be possible. Others confirm the derived ratio and express understanding of the situation.

Contextual Notes

There is an indication that the original poster is experiencing fatigue, which may affect their clarity of thought. The discussion does not provide specific values for p or n, which limits further exploration of the problem.

courtrigrad
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Hello all

I am having a little mental lapse.

If the average score of p students is 70 and the average score of n students is 92, and the average of the scores of p and n is 86, what is p/n?

(70p + 92n)/ ( p + n ) = 86

70p + 92n = 86(p+n)

70p + 92n = 86p +86n
92n = 16p + 86n
6n = 16p
p = 3/8n
n= 8/3p

Where do I go from here (sorry was awake for whole night)

Thanks
 
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Unless you're given either n or p, you're done. You have the ratio between n and p.

If n is 24 students, then p is 9 students; if n is 48 students, then p is 18 students, etc.
 
You're 'home'. :smile:If
[tex]p=\frac{3}{8}n[/tex]
,then
[tex]\frac{p}{n}=\frac{3}{8}[/tex]

,okay??

Daniel.
 
lol

thanks dextercioby

guess it was because i stayed up
 

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