(1.0 / 2) process repeated 5 times; what is the algrabraic formula?by mr magoo Tags: algrabraic, formula, process, repeated, times 

#1
Mar3112, 02:27 PM

P: 23

1 / 2 = 0.5
0.5 / 2 = 0.25 0.25 / 2 = 0.125 0.125 / 2 = 0.0625 0.0625 / 2 = 0.03125 What is the algebraic formula for this? 



#2
Mar3112, 02:35 PM

P: 1,623

[itex]\frac{1}{2^5}[/itex]




#3
Mar3112, 02:44 PM

P: 23

This is a new one;
64 / 2 = 32 32 / 2 = 16 16 / 2 = 8 8 / 2 = 4 4 / 2 = 2 2 / 2 = 1 1 / 2 = 0.5 0.5 / 2 = 0.25 0.25 / 2 = 0.125 0.125 / 2 = 0.0625 0.0625 / 2 = 0.03125 [itex]\frac{64}{2^{10}}[/itex] 



#4
Mar3112, 02:49 PM

P: 23

(1.0 / 2) process repeated 5 times; what is the algrabraic formula?
Thanks.




#5
Mar3112, 02:50 PM

P: 1,623

That should actually be [itex]\frac{64}{2^{11}}[/itex].
Edit: Enclose your "10" in { } to make it appear correctly. 



#6
Mar3112, 02:52 PM

P: 23

Your right, I added one too many and thought there was only ten.




#7
Mar3112, 02:59 PM

P: 23

Thanks for the editing tip.




#8
Mar3112, 04:31 PM

PF Gold
P: 1,930

[tex]\frac{1}{2^n}[/tex] is a formula. 



#9
Mar3112, 05:08 PM

P: 1,623





#10
Apr112, 09:10 PM

HW Helper
P: 3,436

[tex]\frac{64}{2^{10}}=\frac{2^5}{2^{10}}[/tex] And if you remember the rule of indices, [tex]\frac{2^a}{2^b}=2^{ab}[/tex] so [tex]\frac{2^5}{2^{10}}=2^{510}=2^{5}=\frac{1}{2^5}[/tex] As we got in your first question. 



#11
Apr212, 06:06 PM

HW Helper
P: 6,931

The formula (not sure if this is considered algebraic) or notation for a product series in the original example would be:
[tex]\prod_{i=1}^5 \ \frac{1}{2} [/tex] 


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