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If z is one of the roots of unity with index n, find the sum |
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| Apr8-12, 03:49 AM | #1 |
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If z is one of the roots of unity with index n, find the sum
1. The problem statement, all variables and given/known data
Given the fact that z is one of the n-th roots of unity, find the sum below: 1 + 2z + 3z2 + ... + nzn-1 2. Relevant equations (1-x)(1+x+...+xn-1) = 1 - xn 3. The attempt at a solution honestly I don't know how to do this. any help is appreciated |
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| Apr8-12, 04:53 AM | #2 |
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..the hint for the solution is called complete induction. ;)
First of all you starting to show that the beginning of the sequence is true. After that you show that its also true for n+1... Try to make some sort of attempt to solve it... |
| Apr8-12, 05:02 AM | #3 |
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Divide eqn 2 with (1-x) and try solvin it using some calculus
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| Apr8-12, 05:06 AM | #4 |
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If z is one of the roots of unity with index n, find the sum
Yes u can use induction also. But try solving it using calculus. It is simpler and more intrestring
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| Apr8-12, 05:42 AM | #5 |
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what I'm trying to solve is this
1 + 2z + 3z2 + ... + nzn-1 |
| Apr8-12, 06:36 AM | #6 |
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Yes, you said that initially and you have two different suggestions as to how to do that. Have you tried either?
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| Apr10-12, 12:14 PM | #7 |
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I don't know how to apply induction to a sum. there is no "=" to prove. I have to find the sum, not prove something given. That's why I don't know how to apply induction.
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| Apr10-12, 02:09 PM | #8 |
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| Apr10-12, 03:46 PM | #9 |
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Recognitions:
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| Apr10-12, 04:33 PM | #10 |
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Recognitions:
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Hint: What do you get if you differentiate x+x^2+...+x^n?
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