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If z is one of the roots of unity with index n, find the sum

 
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Apr8-12, 03:49 AM   #1
 

If z is one of the roots of unity with index n, find the sum


1. The problem statement, all variables and given/known data
Given the fact that z is one of the n-th roots of unity, find the sum below:
1 + 2z + 3z2 + ... + nzn-1


2. Relevant equations

(1-x)(1+x+...+xn-1) = 1 - xn

3. The attempt at a solution
honestly I don't know how to do this. any help is appreciated
 
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Apr8-12, 04:53 AM   #2
 
..the hint for the solution is called complete induction. ;)

First of all you starting to show that the beginning of the sequence is true.
After that you show that its also true for n+1...

Try to make some sort of attempt to solve it...
 
Apr8-12, 05:02 AM   #3
 
Divide eqn 2 with (1-x) and try solvin it using some calculus
 
Apr8-12, 05:06 AM   #4
 

If z is one of the roots of unity with index n, find the sum


Yes u can use induction also. But try solving it using calculus. It is simpler and more intrestring
 
Apr8-12, 05:42 AM   #5
 
what I'm trying to solve is this
1 + 2z + 3z2 + ... + nzn-1
 
Apr8-12, 06:36 AM   #6
 
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Yes, you said that initially and you have two different suggestions as to how to do that. Have you tried either?
 
Apr10-12, 12:14 PM   #7
 
I don't know how to apply induction to a sum. there is no "=" to prove. I have to find the sum, not prove something given. That's why I don't know how to apply induction.
 
Apr10-12, 02:09 PM   #8
 
Quote by tonit View Post


2. Relevant equations

(1-x)(1+x+...+xn-1) = 1 - xn
There is one relevant eqn missing
 
Apr10-12, 03:46 PM   #9
 
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Quote by tonit View Post
I don't know how to apply induction to a sum. there is no "=" to prove. I have to find the sum, not prove something given. That's why I don't know how to apply induction.
I'm guessing that you're supposed to find a formula for the series (without 3 dots in it).
 
Apr10-12, 04:33 PM   #10
 
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Hint: What do you get if you differentiate x+x^2+...+x^n?
 
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