|Jan12-05, 09:01 AM||#1|
Heat Capacity iron heating water
This is what I've got:
Iron mass: 81.9g
Initial iron temp.: 92'C
Water volume: 100mL
Initial water temp.: 25'C
Final water temp.: 29'C
What the the experimental heat capacity of iron?
|Jan12-05, 10:39 AM||#2|
Bjorn, do you know what equation is to be used for this kind of problem. It's very simple and will be in your textbook. Look it up.
We can not do your homework for you. You have to make an attempt first.
|Jan12-05, 12:08 PM||#3|
How about this, does this seem correct?
mm = 81.9g
mw = 100mL
Tim = 92°C
Tf = 29°C
Tiw = 25°C
Tfw = 29°C
cw = 4.19 J/g·°C (this is the number the school operates with)
cm = ?
81.9g(cm)(29°C - 92°C)+100g(4.19J/g·°C)(29°C - 25°C) = 0
81.9g(cm)(-63°C)+100g(4.19J/g·°C)(4°C) = 0
-5159.7g·°C(cm)+1676J = 0
1676J = 5159.7g·°C(cm)
Divide both sides by 5159.7g·°C:
cm = 0.325J/g·°C
Didn't take this from the text book, I guess I knew what to do, but I have always been an idiot with unkowns in math
Equations and me aren't exactly best friends.
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