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Gas Manometerby samantha.
Tags: manometer 
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#1
Apr1212, 04:38 PM

P: 15

1. The problem statement, all variables and given/known data
Consider a manometer with a glass bulb (Pgas=88kPa) at one end and which is open to the atmosphere (P =101 kPa) at the other. The manometer has two liquids oil and water in it, as shown. If the oil has a density of 823 kg/m3 and water a density of 1.00x10^3 kg/m3 find the height of the water. http://s16.postimage.org/9ihj14zir/S...3_22_43_PM.png 2. Relevant equations P=pgh 3. The attempt at a solution I keep deducing the equation to be; Patm + ρwater*g*H = Pgas + ρoil*g*0.699m Solving for H, I get 0.750m. The answer though, is 0.269m. Where am I going wrong? 


#2
Apr1212, 09:34 PM

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PF Gold
P: 1,948

I'm guessing the pressure of the gas should be 98 kPa, not 88. It was probably a typo of some sort. (And just to be nitpicky about this problem, what is the water doing "floating" on oil? Oil is lighter that water. The water would sink to the bottom, and the oil would slurp up replacing the water at the top. Well, unless there's some sort of hidden barrier separating them. Anyway, good luck with it. ) 


#3
Apr1212, 09:42 PM

P: 15

88kPa is the value given. If it was a typo it wasn't on my part. I noticed the water floating on top of oil.. strange yes. Haha.
I spent half of my night panicking over my exam tomorrow, trying to figure out where I was going wrong in all of these problems that my professor gave me when in fact there's an issue with almost every question. Thanks for the reply though. :) 


#4
Apr1212, 09:50 PM

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PF Gold
P: 1,948

Gas Manometer
By the way, I think your approach to this problem was valid. Try replacing 88 kPa with 98 kPa, and see what happens.
Good luck on your exam tomorrow! 


#5
Apr1212, 09:53 PM

P: 15

Thank you, Sir. :)



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