What is the rebound speed of a bumper car after colliding with a wall?

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Homework Help Overview

The problem involves a 450kg bumper car colliding with a solid wall at a speed of 2m/s, with a spring constant of 3x10^7 N/m and a maximum compression of 7.7mm. The original poster seeks to determine the rebound speed of the car after the collision.

Discussion Character

  • Exploratory, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants discuss the relationship between potential energy from the spring and kinetic energy, questioning how energy conservation applies to the scenario. Some express uncertainty about the role of friction and the lack of information regarding the surface on which the car travels.

Discussion Status

Multiple interpretations of the problem are being explored, with some participants suggesting that energy losses due to friction must be accounted for. There is no explicit consensus on the correct rebound speed, as different calculations yield varying results.

Contextual Notes

Participants note the absence of details regarding the surface conditions and potential energy losses, which may affect the outcome of the calculations.

futb0l
A 450kg bumper car, with a spring which have a spring constant of 3x10^7 N/m collides at a speed of 2m/s with a solid wall. It gives a maximum compression of 7.7mm. At what speed will the car rebound of the wall?

I am having trouble with this one... I don't know how to go about solving the problem. The answer btw is 1.6m/s
 
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Do you know how to find the potential energy from the spring constant and compression? You should have a formula for that and a formula for kinetic energy as a function of speed. Once the car has rebounded, all that potential energy becomes kinetic energy.
 
HallsofIvy said:
Do you know how to find the potential energy from the spring constant and compression? You should have a formula for that and a formula for kinetic energy as a function of speed. Once the car has rebounded, all that potential energy becomes kinetic energy.

Since the final speed is not equal to the initial speed isn't there some friction involved in this question??

DOes the question say anything about the surface upon which this car travels??
 
stunner5000pt said:
Since the final speed is not equal to the initial speed isn't there some friction involved in this question??

DOes the question say anything about the surface upon which this car travels??

Nope, it doesn't say anything about the surface, it says its just a solid wall... which is why it is strange.
 
futb0l said:
I am having trouble with this one... I don't know how to go about solving the problem. The answer btw is 1.6m/s

Are you sure about this ?

I get 1.9762 m/s

Use energy conservation.

KE (before collision) = PE (at max compression) + E (lost to friction)

Plugging in the numbers, you can find E (lost).

During the rebound, you will lose this same amount of energy to friction, so KE (final) = PE - E (lost)
 
Gokul43201 said:
Are you sure about this ?

I get 1.9762 m/s
I agree. The car has 900 Joules of energy (.5mv^2=.5*450*2*2). A spring compression of .0077 m contains 899.35 joules of energy. If it loses another 10.65 joules in converting it back to kinetic energy, you end up with 878.7 J, so v^2=2*878.7/450; v=1.9762. A speed of 1.6 m. gives the car 576 J. The problem contains no information to account for such a loss of energy.

AM
 
That (1.6 m)answer would require either a spring constant of about 2.5 * 10^7 N/m or a compression of about 7.0 mm or just a whole new set of numbers.
 
Thanks, probably something wrong with this question, I am stunned myself.
 

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