shape of H2SO4

FBInstant

I tried to use VSERP to draw the shape of H2SO4
but consider
S :6 (group6)
4O :2*4
2H :1*2
-----------
16=>4pi bond
but then 4 pi bond of oxygen=16 electrons
how about the sigma bond of 2 hydrogen

thunderfvck

From memory SO4(-2) has the S as the central atom, two O's oppositely have a pi bond, and the remaining two have sigma bonds each with a negative charge. The H's are attached to these O's.

FBInstant

but then it becomes
S:6
2O:1*2(sigma)
2O:2*2(pi)
2H:1*2
----------
14
but 2pi+4sigma=16
again, it does not work

GoneRogue

Hint: Look at your electron count and then look at the charge on sulfuric acid.