|Apr27-12, 07:43 AM||#1|
probability doubt - where am i wrong?
There is a dice where probability of obtaining a number is proportional to the number itself.
I have done these problems and the probabilties are 1/21, 2/21,/3/21,/4/21,/5/21 and 6/21
In a normal dice when you have to find probabilities of say, 2 and 4 we do it by favourable cases / total number of cases = 2/6 = 1/3
But you cant apply that method in this case - i know that but why?
Probability of 2 or 4 in this case would be 2/21 + 4/21 = 6/21
but why cant we do this by favourable cases / total number of cases?
|Apr27-12, 05:31 PM||#2|
|Apr30-12, 01:42 PM||#3|
Check the three drawbacks of "Classical" definition.
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