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Probability doubt  where am i wrong? 
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#1
Apr2712, 07:43 AM

P: 260

There is a dice where probability of obtaining a number is proportional to the number itself.
I have done these problems and the probabilties are 1/21, 2/21,/3/21,/4/21,/5/21 and 6/21 In a normal dice when you have to find probabilities of say, 2 and 4 we do it by favourable cases / total number of cases = 2/6 = 1/3 But you cant apply that method in this case  i know that but why? Probability of 2 or 4 in this case would be 2/21 + 4/21 = 6/21 but why cant we do this by favourable cases / total number of cases? 


#2
Apr2712, 05:31 PM

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P: 26,148

hi jd12345!



#3
Apr3012, 01:42 PM

P: 240

Check the three drawbacks of "Classical" definition.



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