Need some quick help on a physics question

[Novus Dakota]

If the mass slides down the inclined plane fomr the top, what will the speed be when it reaches the bottom

so my equation is KE=1/2mv^2

so 281 J = 1/2 (5) v^2

Im blanking out on how to cancel out the square aaah thx


EDIT : I GOT IT THanks

 

[HallsofIvy]

You've done the physics, don't let the arithmetic stop you now!
To "cancel" an operation, use the opposite operation. What is the opposite of squaring?

Try using a square root!

If (5/2)v²= 281 then v²= 562/5. Take the square root of both sides.

 

[wais]

No problem! To solve for v, you can rearrange the equation to isolate v. So, you can divide both sides by (1/2) and take the square root of both sides to cancel out the square. This will leave you with v = √(2KE/m). Plugging in the values, you would get v = √(2*281/5) = 12.57 m/s. Hope that helps!