Conversion from aircraft bearing to normal degrees

michael atlas

I have a list of bearings that I want to convert. The normal degrees circle is oriented with 0 to 360 going counter clockwise. I have degrees calculations that require this. I have a set of data from bearings from an aircraft where I need to convert those bearings to normal degrees bearings. As in, the bearings that I have are oriented 90 degrees out of phase and they go from 0 to 360 clock wise.

Attached is a picture of what I mean.

Does anyone know a formula to do this for any bearing to normal degrees?

Studiot

What was wrong with the method I gave you in your earlier thread?

michael atlas

I did not realise it until I had to present the data that I used the formula for in the code that I wrote, but the bearing was off. The bearing that aircraft use orients the degreesfrom 0 at north to 90 at east, to 180 at south, etc. The bearings that I had where I needed that formula for were oriented that way. That code worked only for bearings that were oriented in the way standard mathematics works: as in for the unit circle; 0 degrees is oriented on the right side of the circle and it increments up to 360 degrees as you go counter clock wise on the circle.

So for example, when I have a bearing that is 270 degrees, the code tells me the new lat and long was at a bearing of 90 degrees. and vice versa.

I had to convert my bearings to the standard orientation in math for 0, 90 180, 270, 360 unit circle. It's fine now because I figured out the conversion.

R/
Mike

Studiot

Mebbe so, but the formulae I posted before were already corrected.

Attached is a flowchart for programming the conventional non corrected formulae.

Attached Thumbnails

 

Andre

Hmm I wonder if compass bearing in degrees=Mod(90-x,360) wouldn't do the trick.

Studiot

I gave the formulae,( but not the theory) in this thread

http://www.physicsforums.com/showthread.php?t=605218

the relevant formulae are

ΔN = Rsin(450-wcb)
ΔE = Rcos(450-wcb)