Atwood Machine simulation problem

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Homework Help Overview

The discussion revolves around an Atwood Machine simulation involving two masses, m1 and m2, with specific values and conditions. The focus is on determining the normal force exerted by the floor on m2 and the tension in the rope at a specified time during the simulation.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between the normal force, tension, and gravitational force acting on m2 in equilibrium. Some question the relevance of the time parameter in the context of the problem.

Discussion Status

There is ongoing clarification regarding the definitions of the forces involved and the conditions of equilibrium. Some participants express confidence in the calculations presented, while others seek further understanding of the implications of the time variable.

Contextual Notes

The discussion includes assumptions about equilibrium conditions and the specific setup of the Atwood Machine simulation. The relevance of the time at which the tension is measured is also under scrutiny.

extreme
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Need a check on this one please. In an Atwood Machine simulation, m1 is 1.0kg and m2 is 1.1kg. m2 rests on the floor that exerts a normal force, Fn, on m2. when the system is in equalibrium, the tension, T, in the rope at 2.54s is 9.789. If Fn +T- m2*g = 0 then Fn = .991. Is this correct?
 
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equilibrium

If the question is "What normal force does the floor exert on m2 when m2 rests on the floor?" then you're probably OK. (Although I have no idea what 2.54s has to do with anything.)

The forces on m2 are: [itex]F_n + T - m_2 g = 0[/itex]; similarly, the forces on m1 are: [itex]T - m_1 g = 0[/itex]. So [itex]F_n = (m_2 - m_1)g[/itex].
 
equilibrium

The question "What is the normal force, FN, and what is the tension, T, in the rope? T (at t = 2.54s) = ______. At equilibrium: FN + T – m2 • g = 0. Then FN = _______." This is a timed simulation and at 2.54s the rope tension,T, is 9.789
 
extreme said:
The question "What is the normal force, FN, and what is the tension, T, in the rope? T (at t = 2.54s) = ______. At equilibrium: FN + T – m2 • g = 0. Then FN = _______." This is a timed simulation and at 2.54s the rope tension,T, is 9.789
OK, now I see what you're talking about. Since T is given and equilibrium is assumed, your answer is correct; rounded off, the normal force would be 1.0 N.
 
equilibrium

Thanks for the quick reply.
 

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