- #1
τheory
- 43
- 0
Homework Statement
Why is the electron configuration of neutral Platinum:
[itex]Pt = [Xe]4f ^{14} 5d ^{9} 6s ^{1}[/itex]
and not?:
[itex]Pt = [Xe]4f ^{14} 5d ^{10} 6s ^{0}[/itex]
I thought that if the two electrons from the 6s sub-shell were to move to the 5d sub-shell, then 5d sub-shell would be fully paired, hence stability? However, this is not the case as the actual configuration calls for only one electron to be moved from the 6s sub-shell, rather than two. Can someone explain to me why this is the case?