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Fourier Transform help! (bit urgent) |
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| Jun11-12, 05:20 AM | #1 |
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Fourier Transform help! (bit urgent)
Hi there,
I'm having a recurring problem with my fourier transforms that I have tried really hard to figure out but I feel like I'm missing something important. It keeps popping up in my communications and signal processing papers. I keep getting FTs like: ∫e^(j2π(n/2T - f)t).dt Does this reduce to anything? I've tried for a few hours to understand it and I'm pretty much stuck. If I had the fundamental frequency then it would make more sense to me, but I don't. The question involves finding the FT of: e^(jπn(t/T) Thanks in advance for any help!! Ben |
| Jun11-12, 05:32 AM | #2 |
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Assuming all your other parameters are constant or not related to t, You should be able to use the fact that integrating e^(at)dt gives 1/a x e^(at) for the anti-derivative. Is the above true or is your integral in terms of something more complicated where the a, above is in terms of a function of t? |
| Jun11-12, 05:58 AM | #3 |
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Thanks for the quick reply chiro!
Yeah, I did try that, but because I'm integrating over limits from -∞ to +∞ (the signal is a pulse train) then I get an undefined result: 1/(n/2T - f) * sin(2π*(n/2T - f)*∞) - that's after converting from exponentials into sine form. Should I be using these limits? I guess that the frequency content of a periodic signal is the same for each period right? |
| Jun11-12, 08:23 AM | #4 |
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Fourier Transform help! (bit urgent) |
| Jun11-12, 08:40 AM | #5 |
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Sorry I'm misunderstanding a bit. You can represent the pulse train as an infinite summation of sinusoids (hence the n in the equation), but I moved the summation sign outside the integral due to linearity properties of the FT - the pulse is actually a sinc function itself. (I think) The problem I'm trying to solve doesn't say what the pulse train is doing, but it's likely being used for sampling, in which case I thought it theoretically did go from -infinity to +infinity. The original question is: Find the fourier transform of: (A/T) Ʃ sinc(πn(tau/T)) * e^(jπn(tau/T)) * e^(jπn(t/T)) T is the period, and tau/T is the mark-to-space ratio. My answer is: A Ʃ sinc(πn(tau/T)) * e^(jπn(tau/T)) * sinc(π(n/2T - f)T) The answer isn't given.. Thanks again for the replies!! |
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